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665 B
665 B
// 如何转化为01背包问题
尽量让石头分成,重量相同的两堆,这样就化解成 01背包问题了。
class Solution {
public:
int lastStoneWeightII(vector<int>& stones) {
vector<int> dp(30001, 0);
int sum = 0;
for (int i = 0; i < stones.size(); i++) sum += stones[i];
int target = sum / 2;
for (int i = 0; i < stones.size(); i++) {
for (int j = target; j >= 0; j--) {
if (j - stones[i] >= 0) {
dp[j] = max(dp[j], dp[j - stones[i]] + stones[i]);
}
}
}
return sum - dp[target] - dp[target];
}
};