Merge branch 'youngyangyang04:master' into remote

This commit is contained in:
Arthur Pan
2022-01-26 09:26:51 +00:00
committed by GitHub
6 changed files with 218 additions and 129 deletions

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@ -346,69 +346,56 @@ class Solution {
### Go
```Go
import "strings"
var res [][]string
func isValid(board [][]string, row, col int) (res bool){
n := len(board)
for i:=0; i < row; i++ {
if board[i][col] == "Q" {
return false
}
}
for i := 0; i < n; i++{
if board[row][i] == "Q" {
return false
}
}
for i ,j := row, col; i >= 0 && j >=0 ; i, j = i - 1, j- 1{
if board[i][j] == "Q"{
return false
}
}
for i, j := row, col; i >=0 && j < n; i,j = i-1, j+1 {
if board[i][j] == "Q" {
return false
}
}
return true
}
func backtrack(board [][]string, row int) {
size := len(board)
if row == size{
temp := make([]string, size)
for i := 0; i<size;i++{
temp[i] = strings.Join(board[i],"")
}
res =append(res,temp)
return
}
for col := 0; col < size; col++ {
if !isValid(board, row, col){
continue
}
board[row][col] = "Q"
backtrack(board, row+1)
board[row][col] = "."
}
}
func solveNQueens(n int) [][]string {
res = [][]string{}
board := make([][]string, n)
for i := 0; i < n; i++{
board[i] = make([]string, n)
}
for i := 0; i < n; i++{
for j := 0; j<n;j++{
board[i][j] = "."
}
}
backtrack(board, 0)
var res [][]string
chessboard := make([][]string, n)
for i := 0; i < n; i++ {
chessboard[i] = make([]string, n)
}
for i := 0; i < n; i++ {
for j := 0; j < n; j++ {
chessboard[i][j] = "."
}
}
var backtrack func(int)
backtrack = func(row int) {
if row == n {
temp := make([]string, n)
for i, rowStr := range chessboard {
temp[i] = strings.Join(rowStr, "")
}
res = append(res, temp)
return
}
for i := 0; i < n; i++ {
if isValid(n, row, i, chessboard) {
chessboard[row][i] = "Q"
backtrack(row + 1)
chessboard[row][i] = "."
}
}
}
backtrack(0)
return res
}
return res
func isValid(n, row, col int, chessboard [][]string) bool {
for i := 0; i < row; i++ {
if chessboard[i][col] == "Q" {
return false
}
}
for i, j := row-1, col-1; i >= 0 && j >= 0; i, j = i-1, j-1 {
if chessboard[i][j] == "Q" {
return false
}
}
for i, j := row-1, col+1; i >= 0 && j < n; i, j = i-1, j+1 {
if chessboard[i][j] == "Q" {
return false
}
}
return true
}
```
### Javascript

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@ -266,46 +266,33 @@ Go
```go
func uniquePathsWithObstacles(obstacleGrid [][]int) int {
m,n:= len(obstacleGrid),len(obstacleGrid[0])
m, n := len(obstacleGrid), len(obstacleGrid[0])
// 定义一个dp数组
dp := make([][]int,m)
for i,_ := range dp {
dp[i] = make([]int,n)
dp := make([][]int, m)
for i, _ := range dp {
dp[i] = make([]int, n)
}
// 初始化
for i:=0;i<m;i++ {
// 如果是障碍物, 后面的就都是0, 不用循环了
if obstacleGrid[i][0] == 1 {
break
}
dp[i][0]=1
// 初始化, 如果是障碍物, 后面的就都是0, 不用循环了
for i := 0; i < m && obstacleGrid[i][0] == 0; i++ {
dp[i][0] = 1
}
for i:=0;i<n;i++ {
if obstacleGrid[0][i] == 1 {
break
}
dp[0][i]=1
for i := 0; i < n && obstacleGrid[0][i] == 0; i++ {
dp[0][i] = 1
}
// dp数组推导过程
for i:=1;i<m;i++ {
for j:=1;j<n;j++ {
// 如果obstacleGrid[i][j]这个点是障碍物, 那么我们的dp[i][j]保持为0
if obstacleGrid[i][j] != 1 {
for i := 1; i < m; i++ {
for j := 1; j < n; j++ {
// 如果obstacleGrid[i][j]这个点是障碍物, 那么dp[i][j]保持为0
if obstacleGrid[i][j] != 1 {
// 否则我们需要计算当前点可以到达的路径数
dp[i][j] = dp[i-1][j]+dp[i][j-1]
dp[i][j] = dp[i-1][j] + dp[i][j-1]
}
}
}
// debug遍历dp
//for i,_ := range dp {
// for j,_ := range dp[i] {
// fmt.Printf("%.2v,",dp[i][j])
// }
// fmt.Println()
//}
return dp[m-1][n-1]
}
```
Javascript

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@ -730,5 +730,33 @@ bool isBalanced(struct TreeNode* root){
}
```
## Swift:
>递归
```swift
func isBalanced(_ root: TreeNode?) -> Bool {
// -1 已经不是平衡二叉树
return getHeight(root) == -1 ? false : true
}
func getHeight(_ root: TreeNode?) -> Int {
guard let root = root else {
return 0
}
let leftHeight = getHeight(root.left)
if leftHeight == -1 {
return -1
}
let rightHeight = getHeight(root.right)
if rightHeight == -1 {
return -1
}
if abs(leftHeight - rightHeight) > 1 {
return -1
} else {
return 1 + max(leftHeight, rightHeight)
}
}
```
-----------------------
<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>

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@ -553,6 +553,65 @@ function reverse(strArr, start, end) {
}
```
TypeScript
```typescript
function reverseWords(s: string): string {
/** Utils **/
// 删除多余空格, 如' hello world ' => 'hello world'
function delExtraSpace(arr: string[]): void {
let left: number = 0,
right: number = 0,
length: number = arr.length;
while (right < length && arr[right] === ' ') {
right++;
}
while (right < length) {
if (arr[right] === ' ' && arr[right - 1] === ' ') {
right++;
continue;
}
arr[left++] = arr[right++];
}
if (arr[left - 1] === ' ') {
arr.length = left - 1;
} else {
arr.length = left;
}
}
// 翻转字符串,如:'hello' => 'olleh'
function reverseWords(strArr: string[], start: number, end: number) {
let temp: string;
while (start < end) {
temp = strArr[start];
strArr[start] = strArr[end];
strArr[end] = temp;
start++;
end--;
}
}
/** Main code **/
let strArr: string[] = s.split('');
delExtraSpace(strArr);
let length: number = strArr.length;
// 翻转整个字符串
reverseWords(strArr, 0, length - 1);
let start: number = 0,
end: number = 0;
while (start < length) {
end = start;
while (strArr[end] !== ' ' && end < length) {
end++;
}
// 翻转单个单词
reverseWords(strArr, start, end - 1);
start = end + 1;
}
return strArr.join('');
};
```
Swift:
```swift

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@ -581,7 +581,72 @@ var binaryTreePaths = function(root) {
};
```
Swift:
> 递归/回溯
```swift
func binaryTreePaths(_ root: TreeNode?) -> [String] {
var res = [String]()
guard let root = root else {
return res
}
var path = [Int]()
_binaryTreePaths(root, path: &path, res: &res)
return res
}
func _binaryTreePaths(_ root: TreeNode, path: inout [Int], res: inout [String]) {
path.append(root.val)
if root.left == nil && root.right == nil {
var str = ""
for i in 0 ..< path.count - 1 {
str.append("\(path[i])->")
}
str.append("\(path.last!)")
res.append(str)
return
}
if let left = root.left {
_binaryTreePaths(left, path: &path, res: &res)
path.removeLast()
}
if let right = root.right {
_binaryTreePaths(right, path: &path, res: &res)
path.removeLast()
}
}
```
> 迭代
```swift
func binaryTreePaths(_ root: TreeNode?) -> [String] {
var res = [String]()
guard let root = root else {
return res
}
var stackNode = [TreeNode]()
stackNode.append(root)
var stackStr = [String]()
stackStr.append("\(root.val)")
while !stackNode.isEmpty {
let node = stackNode.popLast()!
let str = stackStr.popLast()!
if node.left == nil && node.right == nil {
res.append(str)
}
if let left = node.left {
stackNode.append(left)
stackStr.append("\(str)->\(left.val)")
}
if let right = node.right {
stackNode.append(right)
stackStr.append("\(str)->\(right.val)")
}
}
return res
}
```
-----------------------
<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>

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@ -289,7 +289,7 @@ func findTargetSumWays(nums []int, target int) int {
for _, v := range nums {
sum += v
}
if target > sum {
if abs(target) > sum {
return 0
}
if (sum+target)%2 == 1 {
@ -311,49 +311,12 @@ func findTargetSumWays(nums []int, target int) int {
}
return dp[bag]
}
```
> 更新版上一个跑不通了因为会存在bag 小于0的情况
```go
func findTargetSumWays(nums []int, target int) int {
//先转化为数学问题
//a-b=target
//a+b=sum
//a=(target+sum)/2
//求出sum
var sum int
for _,value:=range nums{
sum+=value
}
//如果sum<target或者 sum+target不是偶数因为a是int 或者两者之和小于0了
if sum<target||(sum+target)%2==1||(sum+target)<0{
return 0
}
//开始dp初始化
dp:=make([][]int,len(nums)+1)
for i:=0;i<=len(nums);i++{
tmp:=make([]int,(target+sum)/2+1)//背包容量
dp[i]=tmp
}
dp[0][0]=1//当背包容量为0且物品为0时填满背包就1种方法
for i:=0;i<len(nums)+1;i++{
if i==0{
continue
}
for j:=0;j<(target+sum)/2+1;j++{
if nums[i-1]<=j{//如果背包装的下
dp[i][j]=dp[i-1][j]+dp[i-1][j-nums[i-1]]
}else{
dp[i][j]=dp[i-1][j]
}
}
}
return dp[len(nums)][(target+sum)/2]
func abs(x int) int {
return int(math.Abs(float64(x)))
}
```
Javascript
```javascript
const findTargetSumWays = (nums, target) => {