Update 0019.删除链表的倒数第N个节点.md

修改python版本为：fast先走n+1步（旧版本是fast走n步，然后判断fast.next!=None），这样与上面的讲解一致
2025-07-09 03:34:02 +08:00 · 2023-03-05 16:21:15 -05:00
parent 408c8f3ae9
commit 5e08d1b810
1 changed files with 2 additions and 2 deletions
--- a/problems/0019.删除链表的倒数第N个节点.md
+++ b/problems/0019.删除链表的倒数第N个节点.md
@ -129,10 +129,10 @@ class Solution:
        head_dummy.next = head

        slow, fast = head_dummy, head_dummy
-        while(n!=0): #fast先往前走n步
+        while(n>=0): #fast先往前走n+1步
            fast = fast.next
            n -= 1
-        while(fast.next!=None):
+        while(fast!=None):
            slow = slow.next
            fast = fast.next
        #fast 走到结尾后，slow的下一个节点为倒数第N个节点