mirror of
https://github.com/halfrost/LeetCode-Go.git
synced 2025-07-28 22:51:54 +08:00
151 lines
3.8 KiB
Markdown
Executable File
151 lines
3.8 KiB
Markdown
Executable File
# [706. Design HashMap](https://leetcode.com/problems/design-hashmap/)
|
||
|
||
|
||
## 题目
|
||
|
||
Design a HashMap without using any built-in hash table libraries.
|
||
|
||
To be specific, your design should include these functions:
|
||
|
||
- `put(key, value)` : Insert a (key, value) pair into the HashMap. If the value already exists in the HashMap, update the value.
|
||
- `get(key)`: Returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key.
|
||
- `remove(key)` : Remove the mapping for the value key if this map contains the mapping for the key.
|
||
|
||
**Example**:
|
||
|
||
MyHashMap hashMap = new MyHashMap();
|
||
hashMap.put(1, 1);
|
||
hashMap.put(2, 2);
|
||
hashMap.get(1); // returns 1
|
||
hashMap.get(3); // returns -1 (not found)
|
||
hashMap.put(2, 1); // update the existing value
|
||
hashMap.get(2); // returns 1
|
||
hashMap.remove(2); // remove the mapping for 2
|
||
hashMap.get(2); // returns -1 (not found)
|
||
|
||
**Note**:
|
||
|
||
- All keys and values will be in the range of `[0, 1000000]`.
|
||
- The number of operations will be in the range of `[1, 10000]`.
|
||
- Please do not use the built-in HashMap library.
|
||
|
||
|
||
## 题目大意
|
||
|
||
不使用任何内建的哈希表库设计一个哈希映射具体地说,你的设计应该包含以下的功能:
|
||
|
||
- put(key, value):向哈希映射中插入(键,值)的数值对。如果键对应的值已经存在,更新这个值。
|
||
- get(key):返回给定的键所对应的值,如果映射中不包含这个键,返回 -1。
|
||
- remove(key):如果映射中存在这个键,删除这个数值对。
|
||
|
||
注意:
|
||
|
||
- 所有的值都在 [1, 1000000] 的范围内。
|
||
- 操作的总数目在 [1, 10000] 范围内。
|
||
- 不要使用内建的哈希库。
|
||
|
||
|
||
## 解题思路
|
||
|
||
|
||
- 简单题,设计一个 hashmap 的数据结构,要求有 `put(key, value)`,`get(key)`,`remove(key)`,这 3 个方法。设计一个 map 主要需要处理哈希冲突,一般都是链表法解决冲突。
|
||
|
||
|
||
## 代码
|
||
|
||
```go
|
||
|
||
package leetcode
|
||
|
||
const Len int = 100000
|
||
|
||
type MyHashMap struct {
|
||
content [Len]*HashNode
|
||
}
|
||
|
||
type HashNode struct {
|
||
key int
|
||
val int
|
||
next *HashNode
|
||
}
|
||
|
||
func (N *HashNode) Put(key int, value int) {
|
||
if N.key == key {
|
||
N.val = value
|
||
return
|
||
}
|
||
if N.next == nil {
|
||
N.next = &HashNode{key, value, nil}
|
||
return
|
||
}
|
||
N.next.Put(key, value)
|
||
}
|
||
|
||
func (N *HashNode) Get(key int) int {
|
||
if N.key == key {
|
||
return N.val
|
||
}
|
||
if N.next == nil {
|
||
return -1
|
||
}
|
||
return N.next.Get(key)
|
||
}
|
||
|
||
func (N *HashNode) Remove(key int) *HashNode {
|
||
if N.key == key {
|
||
p := N.next
|
||
N.next = nil
|
||
return p
|
||
}
|
||
if N.next != nil {
|
||
return N.next.Remove(key)
|
||
}
|
||
return nil
|
||
}
|
||
|
||
/** Initialize your data structure here. */
|
||
func Constructor706() MyHashMap {
|
||
return MyHashMap{}
|
||
}
|
||
|
||
/** value will always be non-negative. */
|
||
func (this *MyHashMap) Put(key int, value int) {
|
||
node := this.content[this.Hash(key)]
|
||
if node == nil {
|
||
this.content[this.Hash(key)] = &HashNode{key: key, val: value, next: nil}
|
||
return
|
||
}
|
||
node.Put(key, value)
|
||
}
|
||
|
||
/** Returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key */
|
||
func (this *MyHashMap) Get(key int) int {
|
||
HashNode := this.content[this.Hash(key)]
|
||
if HashNode == nil {
|
||
return -1
|
||
}
|
||
return HashNode.Get(key)
|
||
}
|
||
|
||
/** Removes the mapping of the specified value key if this map contains a mapping for the key */
|
||
func (this *MyHashMap) Remove(key int) {
|
||
HashNode := this.content[this.Hash(key)]
|
||
if HashNode == nil {
|
||
return
|
||
}
|
||
this.content[this.Hash(key)] = HashNode.Remove(key)
|
||
}
|
||
|
||
func (this *MyHashMap) Hash(value int) int {
|
||
return value % Len
|
||
}
|
||
|
||
/**
|
||
* Your MyHashMap object will be instantiated and called as such:
|
||
* obj := Constructor();
|
||
* obj.Put(key,value);
|
||
* param_2 := obj.Get(key);
|
||
* obj.Remove(key);
|
||
*/
|
||
|
||
``` |