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# [1295. Find Numbers with Even Number of Digits](https://leetcode.com/problems/find-numbers-with-even-number-of-digits/)
## 题目
Given an array `nums` of integers, return how many of them contain an **even number** of digits.
**Example 1**:
```
Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.
```
**Example 2**:
```
Input: nums = [555,901,482,1771]
Output: 1
Explanation:
Only 1771 contains an even number of digits.
```
**Constraints**:
- `1 <= nums.length <= 500`
- `1 <= nums[i] <= 10^5`
## 题目大意
给你一个整数数组 nums请你返回其中位数为 偶数 的数字的个数。
提示:
- 1 <= nums.length <= 500
- 1 <= nums[i] <= 10^5
## 解题思路
- 给你一个整数数组,要求输出位数为偶数的数字的个数。
- 简单题,把每个数字转换为字符串判断长度是否是偶数即可。
## 代码
```go
func findNumbers(nums []int) int {
res := 0
for _, n := range nums {
res += 1 - len(strconv.Itoa(n))%2
}
return res
}
```