LeetCode-Go/leetcode/1295.Find-Numbers-with-Even-Number-of-Digits/README.md

1295. Find Numbers with Even Number of Digits

题目

Given an array nums of integers, return how many of them contain an even number of digits.

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:

Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.

Constraints:

• 1 <= nums.length <= 500
• 1 <= nums[i] <= 10^5

题目大意

给你一个整数数组 nums，请你返回其中位数为 偶数 的数字的个数。

提示：

• 1 <= nums.length <= 500
• 1 <= nums[i] <= 10^5

解题思路

• 给你一个整数数组，要求输出位数为偶数的数字的个数。
• 简单题，把每个数字转换为字符串判断长度是否是偶数即可。

代码

func findNumbers(nums []int) int {
	res := 0
	for _, n := range nums {
		res += 1 - len(strconv.Itoa(n))%2
	}
	return res
}