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pin rm fails appropriately for indirect pins

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License: MIT
Signed-off-by: Jeromy <jeromyj@gmail.com>
This commit is contained in:
Jeromy
2015-07-10 11:03:15 -07:00
parent 16c4d8cdcb
commit 879cfeeec9
1 changed files with 18 additions and 4 deletions
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22
pin/pin.go
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@ -126,18 +126,26 @@ func (p *pinner) Pin(ctx context.Context, node *mdag.Node, recurse bool) error {
func (p *pinner) Unpin(ctx context.Context, k key.Key, recursive bool) error {
p.lock.Lock()
defer p.lock.Unlock()
if p.recursePin.HasKey(k) {
reason, pinned, err := p.isPinned(k)
if err != nil {
return err
}
if !pinned {
return fmt.Errorf("%s is not pinned", k)
}
switch reason {
case "recursive":
if recursive {
p.recursePin.RemoveBlock(k)
return nil
} else {
return fmt.Errorf("%s is pinned recursively", k)
}
} else if p.directPin.HasKey(k) {
case "direct":
p.directPin.RemoveBlock(k)
return nil
} else {
return fmt.Errorf("%s is not pinned", k)
default:
return fmt.Errorf("%s is pinned indirectly under %s", k, reason)
}
}
@ -151,6 +159,12 @@ func (p *pinner) isInternalPin(key key.Key) bool {
func (p *pinner) IsPinned(k key.Key) (string, bool, error) {
p.lock.RLock()
defer p.lock.RUnlock()
return p.isPinned(k)
}
// isPinned is the implementation of IsPinned that does not lock.
// intended for use by other pinned methods that already take locks
func (p *pinner) isPinned(k key.Key) (string, bool, error) {
if p.recursePin.HasKey(k) {
return "recursive", true, nil
}