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x86: absorb allocation in i386-gen
When generating the mnemonic string table we already set up an identifier for the following entry in a number of cases. Re-use that on the next loop iteration rather than re-doing allocation and conversion.
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@ -1750,13 +1750,15 @@ process_i386_opcodes (FILE *table)
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fprintf (table, "const char i386_mnemonics[] =\n");
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fprintf (table, "const char i386_mnemonics[] =\n");
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fprintf (fp, "\nextern const char i386_mnemonics[];\n\n");
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fprintf (fp, "\nextern const char i386_mnemonics[];\n\n");
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str = NULL;
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for (l = strlen (opcode_array[offs = j = 0]->name); j < i; j++)
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for (l = strlen (opcode_array[offs = j = 0]->name); j < i; j++)
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{
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{
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const char *next = NULL;
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const char *next = NULL;
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size_t l1 = j + 1 < i ? strlen(next = opcode_array[j + 1]->name) : 0;
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size_t l1 = j + 1 < i ? strlen(next = opcode_array[j + 1]->name) : 0;
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name = opcode_array[j]->name;
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name = opcode_array[j]->name;
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str = mkident (name);
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if (str == NULL)
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str = mkident (name);
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if (l < l1 && !strcmp(name, next + l1 - l))
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if (l < l1 && !strcmp(name, next + l1 - l))
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{
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{
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fprintf (fp, "#define MN_%s ", str);
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fprintf (fp, "#define MN_%s ", str);
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@ -1769,8 +1771,9 @@ process_i386_opcodes (FILE *table)
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fprintf (table, " \"\\0\"\"%s\"\n", name);
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fprintf (table, " \"\\0\"\"%s\"\n", name);
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fprintf (fp, "#define MN_%s %#x\n", str, offs + 1);
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fprintf (fp, "#define MN_%s %#x\n", str, offs + 1);
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offs += strlen (name) + 1;
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offs += strlen (name) + 1;
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free (str);
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str = NULL;
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}
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}
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free (str);
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l = l1;
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l = l1;
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}
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}
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