x86: absorb allocation in i386-gen

When generating the mnemonic string table we already set up an
identifier for the following entry in a number of cases. Re-use that on
the next loop iteration rather than re-doing allocation and conversion.
This commit is contained in:
Jan Beulich
2023-01-20 10:16:56 +01:00
parent 3e451ee4a6
commit 992dd393c9

@ -1750,13 +1750,15 @@ process_i386_opcodes (FILE *table)
fprintf (table, "const char i386_mnemonics[] =\n");
fprintf (fp, "\nextern const char i386_mnemonics[];\n\n");
str = NULL;
for (l = strlen (opcode_array[offs = j = 0]->name); j < i; j++)
{
const char *next = NULL;
size_t l1 = j + 1 < i ? strlen(next = opcode_array[j + 1]->name) : 0;
name = opcode_array[j]->name;
str = mkident (name);
if (str == NULL)
str = mkident (name);
if (l < l1 && !strcmp(name, next + l1 - l))
{
fprintf (fp, "#define MN_%s ", str);
@ -1769,8 +1771,9 @@ process_i386_opcodes (FILE *table)
fprintf (table, " \"\\0\"\"%s\"\n", name);
fprintf (fp, "#define MN_%s %#x\n", str, offs + 1);
offs += strlen (name) + 1;
free (str);
str = NULL;
}
free (str);
l = l1;
}