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Another Rust operator precedence bug
My earlier patch to fix PR rust/29859 introduced a new operator precedence bug in the Rust parser. Assignment operators are right-associative in Rust. And, while this doesn't often matter, as Rust assignments always have the value (), still as a matter of principle we should get this correct. Bug: https://sourceware.org/bugzilla/show_bug.cgi?id=29859
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@ -1344,6 +1344,8 @@ rust_parser::parse_binop (bool required)
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OPERATION (ANDAND, 2, logical_and_operation) \
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OPERATION (OROR, 1, logical_or_operation)
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#define ASSIGN_PREC 0
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operation_up start = parse_atom (required);
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if (start == nullptr)
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{
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@ -1376,7 +1378,7 @@ rust_parser::parse_binop (bool required)
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compound_assign_op = current_opcode;
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/* FALLTHROUGH */
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case '=':
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precedence = 0;
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precedence = ASSIGN_PREC;
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lex ();
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break;
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@ -1398,7 +1400,11 @@ rust_parser::parse_binop (bool required)
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break;
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}
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while (precedence <= operator_stack.back ().precedence
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/* Make sure that assignments are right-associative while other
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operations are left-associative. */
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while ((precedence == ASSIGN_PREC
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? precedence < operator_stack.back ().precedence
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: precedence <= operator_stack.back ().precedence)
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&& operator_stack.size () > 1)
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{
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rustop_item rhs = std::move (operator_stack.back ());
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@ -416,3 +416,6 @@ if {[lindex $v 0] >= 8} {
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# The new parser introduced an operator precedence bug.
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gdb_test "print 5 * 7 / 5" " = 7"
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gdb_test "print 4 - 3 - 1" " = 0"
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# Another operator precedence bug.
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gdb_test "print \$one = \$two = 75" " = \\\(\\\)"
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