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63 lines
1.5 KiB
Markdown
63 lines
1.5 KiB
Markdown
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## 题目地址
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https://leetcode-cn.com/problems/permutations/
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## 思路
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先写逻辑,再确认参数,先把for循环写出来,在写 结束语句,在写 函数参数。
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这道题目树形结构还不太一样
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## 解法
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```
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class Solution {
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public:
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vector<vector<int>> result;
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void backtracking (vector<int>& nums, vector<int>& vec, vector<bool>& used) {
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// 此时说明找到了一组
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if (vec.size() == nums.size()) {
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result.push_back(vec);
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return;
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}
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for (int i = 0; i < nums.size(); i++) {
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if (used[i] == false) {
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used[i] = true;
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vec.push_back(nums[i]);
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backtracking(nums, vec, used);
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vec.pop_back();
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used[i] = false;
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}
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}
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}
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vector<vector<int>> permute(vector<int>& nums) {
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vector<bool> used(nums.size(), false);
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vector<int> vec;
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backtracking(nums, vec, used);
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return result;
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}
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};
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```
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这是一个思路:
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class Solution {
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public:
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vector<vector<int>> res;
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vector<vector<int>> permute(vector<int>& nums) {
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solve(nums, 0);
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return res;
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}
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void solve(vector<int> &nums, int idx) {
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if(idx == nums.size()-1 || nums.size() == 0){
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res.push_back(nums);
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return;
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}
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for(int i = idx; i < nums.size(); i++){
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swap(nums[idx], nums[i]);
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solve(nums, idx+1);
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swap(nums[idx], nums[i]);
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}
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}
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};
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