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Update 0110.平衡二叉树.md
修改原有JS版本代码问题
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@ -614,8 +614,10 @@ var isBalanced = function(root) {
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if(node === null) return 0;
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// 3. 确定单层递归逻辑
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let leftDepth = getDepth(node.left); //左子树高度
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let rightDepth = getDepth(node.right); //右子树高度
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// 当判定左子树不为平衡二叉树时,即可直接返回-1
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if(leftDepth === -1) return -1;
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let rightDepth = getDepth(node.right); //右子树高度
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// 当判定右子树不为平衡二叉树时,即可直接返回-1
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if(rightDepth === -1) return -1;
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if(Math.abs(leftDepth - rightDepth) > 1) {
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return -1;
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