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面试题02.07.链表相交 Swift版本
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@ -535,6 +535,45 @@ public ListNode GetIntersectionNode(ListNode headA, ListNode headB)
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}
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```
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### Swift:
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```swift
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func getIntersectionNode(_ headA: ListNode?, _ headB: ListNode?) -> ListNode? {
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var lenA = 0
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var lenB = 0
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var nodeA = headA
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var nodeB = headB
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// 计算链表A和链表B的长度
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while nodeA != nil {
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lenA += 1
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nodeA = nodeA?.next
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}
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while nodeB != nil {
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lenB += 1
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nodeB = nodeB?.next
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}
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// 重置指针
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nodeA = headA
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nodeB = headB
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// 如果链表A更长,让它先走lenA-lenB步
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if lenA > lenB {
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for _ in 0..<(lenA - lenB) {
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nodeA = nodeA?.next
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}
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} else if lenB > lenA {
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// 如果链表B更长,让它先走lenB-lenA步
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for _ in 0..<(lenB - lenA) {
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nodeB = nodeB?.next
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}
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}
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// 同时遍历两个链表,寻找交点
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while nodeA !== nodeB {
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nodeA = nodeA?.next
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nodeB = nodeB?.next
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}
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return nodeA
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}
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```
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<p align="center">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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