mirror of
https://github.com/youngyangyang04/leetcode-master.git
synced 2025-07-07 15:45:40 +08:00
Update 0018.四数之和.md
This commit is contained in:
@ -209,34 +209,38 @@ class Solution {
|
||||
Python:
|
||||
(版本一) 双指针
|
||||
```python
|
||||
def fourSum(self, nums: List[int], target: int) -> List[List[int]]:
|
||||
result = []
|
||||
class Solution:
|
||||
def fourSum(self, nums: List[int], target: int) -> List[List[int]]:
|
||||
nums.sort()
|
||||
for k in range(len(nums)):
|
||||
if nums[k] > target and nums[k] >= 0:
|
||||
n = len(nums)
|
||||
result = []
|
||||
for i in range(n):
|
||||
if nums[i] > target and nums[i] > 0 and target > 0:# 剪枝(可省)
|
||||
break
|
||||
if k > 0 and nums[k] == nums[k-1]:
|
||||
if i > 0 and nums[i] == nums[i-1]:# 去重
|
||||
continue
|
||||
for i in range(k+1, len(nums)):
|
||||
if nums[k] + nums[i] > target and nums[k] + nums[i] >= 0:
|
||||
for j in range(i+1, n):
|
||||
if nums[i] + nums[j] > target and target > 0: #剪枝(可省)
|
||||
break
|
||||
if i > k+1 and nums[i] == nums[i-1]:
|
||||
if j > i+1 and nums[j] == nums[j-1]: # 去重
|
||||
continue
|
||||
left, right = i+1, len(nums)-1
|
||||
while right > left:
|
||||
if nums[k] + nums[i] + nums[left] + nums[right] > target:
|
||||
left, right = j+1, n-1
|
||||
while left < right:
|
||||
s = nums[i] + nums[j] + nums[left] + nums[right]
|
||||
if s == target:
|
||||
result.append([nums[i], nums[j], nums[left], nums[right]])
|
||||
while left < right and nums[left] == nums[left+1]:
|
||||
left += 1
|
||||
while left < right and nums[right] == nums[right-1]:
|
||||
right -= 1
|
||||
left += 1
|
||||
right -= 1
|
||||
elif nums[k] + nums[i] + nums[left] + nums[right] < target:
|
||||
elif s < target:
|
||||
left += 1
|
||||
else:
|
||||
result.append([nums[k], nums[i], nums[left], nums[right]])
|
||||
while right > left and nums[right] == nums[right-1]:
|
||||
right -= 1
|
||||
while right > left and nums[left] == nums[left+1]:
|
||||
left += 1
|
||||
right -= 1
|
||||
left += 1
|
||||
return result
|
||||
|
||||
```
|
||||
(版本二) 使用字典
|
||||
|
||||
|
Reference in New Issue
Block a user