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Update 二叉树的递归遍历.md
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@ -174,50 +174,45 @@ class Solution {
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Python:
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```python
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# 前序遍历-递归-LC144_二叉树的前序遍历
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def preorderTraversal(self, root: TreeNode) -> List[int]:
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# 保存结果
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result = []
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def traversal(root: TreeNode):
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if root == None:
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return
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result.append(root.val) # 前序
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traversal(root.left) # 左
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traversal(root.right) # 右
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if not root:
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return []
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left = self.preorderTraversal(root.left)
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right = self.preorderTraversal(root.right)
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return [root.val] + left + right
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traversal(root)
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return result
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# 中序遍历-递归-LC94_二叉树的中序遍历
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class Solution:
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def inorderTraversal(self, root: TreeNode) -> List[int]:
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result = []
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if root is None:
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return []
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def traversal(root: TreeNode):
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if root == None:
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return
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traversal(root.left) # 左
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result.append(root.val) # 中序
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traversal(root.right) # 右
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left = self.inorderTraversal(root.left)
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right = self.inorderTraversal(root.right)
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traversal(root)
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return result
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return left + [root.val] + right
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# 后序遍历-递归-LC145_二叉树的后序遍历
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class Solution:
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def postorderTraversal(self, root: TreeNode) -> List[int]:
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result = []
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if not root:
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return []
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def traversal(root: TreeNode):
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if root == None:
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return
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traversal(root.left) # 左
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traversal(root.right) # 右
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result.append(root.val) # 后序
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left = self.postorderTraversal(root.left)
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right = self.postorderTraversal(root.right)
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traversal(root)
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return result
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return left + right + [root.val]
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```
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Go:
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