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Merge pull request #108 from Joshua-Lu/patch-25
更新 0700.二叉搜索树中的搜索 Java版本
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@ -141,24 +141,62 @@ public:
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## 其他语言版本
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Java:
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递归法:
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```java
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```Java
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class Solution {
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// 递归,普通二叉树
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public TreeNode searchBST(TreeNode root, int val) {
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if (root == null) return null;
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if (root.val == val) return root;
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else if (root.val > val) return searchBST(root.left, val);
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else return searchBST(root.right, val);
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if (root == null || root.val == val) {
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return root;
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}
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TreeNode left = searchBST(root.left, val);
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if (left != null) {
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return left;
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}
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return searchBST(root.right, val);
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}
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}
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```
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迭代法:
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```java
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class Solution {
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// 递归,利用二叉搜索树特点,优化
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public TreeNode searchBST(TreeNode root, int val) {
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if (root == null || root.val == val) {
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return root;
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}
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if (val < root.val) {
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return searchBST(root.left, val);
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} else {
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return searchBST(root.right, val);
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}
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}
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}
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class Solution {
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// 迭代,普通二叉树
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public TreeNode searchBST(TreeNode root, int val) {
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if (root == null || root.val == val) {
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return root;
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}
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Stack<TreeNode> stack = new Stack<>();
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stack.push(root);
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while (!stack.isEmpty()) {
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TreeNode pop = stack.pop();
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if (pop.val == val) {
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return pop;
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}
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if (pop.right != null) {
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stack.push(pop.right);
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}
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if (pop.left != null) {
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stack.push(pop.left);
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}
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}
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return null;
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}
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}
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class Solution {
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// 迭代,利用二叉搜索树特点,优化,可以不需要栈
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public TreeNode searchBST(TreeNode root, int val) {
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while (root != null)
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if (val < root.val) root = root.left;
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