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Merge branch 'youngyangyang04:master' into master
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@ -486,6 +486,92 @@ class Solution:
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Go:
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> 112. 路径总和
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```go
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//递归法
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/**
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* Definition for a binary tree node.
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* type TreeNode struct {
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* Val int
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* Left *TreeNode
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* Right *TreeNode
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* }
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*/
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func hasPathSum(root *TreeNode, targetSum int) bool {
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var flage bool //找没找到的标志
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if root==nil{
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return flage
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}
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pathSum(root,0,targetSum,&flage)
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return flage
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}
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func pathSum(root *TreeNode, sum int,targetSum int,flage *bool){
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sum+=root.Val
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if root.Left==nil&&root.Right==nil&&sum==targetSum{
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*flage=true
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return
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}
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if root.Left!=nil&&!(*flage){//左节点不为空且还没找到
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pathSum(root.Left,sum,targetSum,flage)
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}
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if root.Right!=nil&&!(*flage){//右节点不为空且没找到
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pathSum(root.Right,sum,targetSum,flage)
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}
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}
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```
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> 113 递归法
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```go
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/**
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* Definition for a binary tree node.
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* type TreeNode struct {
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* Val int
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* Left *TreeNode
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* Right *TreeNode
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* }
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*/
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func pathSum(root *TreeNode, targetSum int) [][]int {
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var result [][]int//最终结果
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if root==nil{
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return result
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}
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var sumNodes []int//经过路径的节点集合
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hasPathSum(root,&sumNodes,targetSum,&result)
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return result
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}
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func hasPathSum(root *TreeNode,sumNodes *[]int,targetSum int,result *[][]int){
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*sumNodes=append(*sumNodes,root.Val)
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if root.Left==nil&&root.Right==nil{//叶子节点
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fmt.Println(*sumNodes)
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var sum int
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var number int
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for k,v:=range *sumNodes{//求该路径节点的和
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sum+=v
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number=k
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}
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tempNodes:=make([]int,number+1)//新的nodes接受指针里的值,防止最终指针里的值发生变动,导致最后的结果都是最后一个sumNodes的值
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for k,v:=range *sumNodes{
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tempNodes[k]=v
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}
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if sum==targetSum{
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*result=append(*result,tempNodes)
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}
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}
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if root.Left!=nil{
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hasPathSum(root.Left,sumNodes,targetSum,result)
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*sumNodes=(*sumNodes)[:len(*sumNodes)-1]//回溯
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}
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if root.Right!=nil{
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hasPathSum(root.Right,sumNodes,targetSum,result)
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*sumNodes=(*sumNodes)[:len(*sumNodes)-1]//回溯
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}
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}
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```
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JavaScript:
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0112.路径总和
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@ -226,6 +226,71 @@ class Solution:
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```
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Go:
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> 递归法
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```go
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/**
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* Definition for a binary tree node.
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* type TreeNode struct {
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* Val int
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* Left *TreeNode
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* Right *TreeNode
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* }
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*/
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func sumOfLeftLeaves(root *TreeNode) int {
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var res int
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findLeft(root,&res)
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return res
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}
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func findLeft(root *TreeNode,res *int){
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//左节点
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if root.Left!=nil&&root.Left.Left==nil&&root.Left.Right==nil{
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*res=*res+root.Left.Val
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}
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if root.Left!=nil{
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findLeft(root.Left,res)
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}
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if root.Right!=nil{
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findLeft(root.Right,res)
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}
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}
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```
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> 迭代法
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```go
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/**
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* Definition for a binary tree node.
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* type TreeNode struct {
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* Val int
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* Left *TreeNode
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* Right *TreeNode
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* }
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*/
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func sumOfLeftLeaves(root *TreeNode) int {
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var res int
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queue:=list.New()
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queue.PushBack(root)
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for queue.Len()>0{
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length:=queue.Len()
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for i:=0;i<length;i++{
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node:=queue.Remove(queue.Front()).(*TreeNode)
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if node.Left!=nil&&node.Left.Left==nil&&node.Left.Right==nil{
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res=res+node.Left.Val
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}
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if node.Left!=nil{
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queue.PushBack(node.Left)
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}
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if node.Right!=nil{
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queue.PushBack(node.Right)
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}
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}
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}
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return res
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}
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```
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JavaScript:
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递归版本
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```javascript
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@ -275,6 +340,7 @@ var sumOfLeftLeaves = function(root) {
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-----------------------
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* 作者微信:[程序员Carl](https://mp.weixin.qq.com/s/b66DFkOp8OOxdZC_xLZxfw)
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* B站视频:[代码随想录](https://space.bilibili.com/525438321)
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@ -298,6 +298,80 @@ class Solution:
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```
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Go:
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> 递归法
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```go
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/**
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* Definition for a binary tree node.
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* type TreeNode struct {
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* Val int
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* Left *TreeNode
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* Right *TreeNode
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* }
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*/
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var maxDeep int // 全局变量 深度
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var value int //全局变量 最终值
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func findBottomLeftValue(root *TreeNode) int {
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if root.Left==nil&&root.Right==nil{//需要提前判断一下(不要这个if的话提交结果会出错,但执行代码不会。防止这种情况出现,故先判断是否只有一个节点)
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return root.Val
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}
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findLeftValue (root,maxDeep)
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return value
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}
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func findLeftValue (root *TreeNode,deep int){
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//最左边的值在左边
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if root.Left==nil&&root.Right==nil{
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if deep>maxDeep{
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value=root.Val
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maxDeep=deep
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}
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}
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//递归
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if root.Left!=nil{
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deep++
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findLeftValue(root.Left,deep)
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deep--//回溯
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}
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if root.Right!=nil{
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deep++
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findLeftValue(root.Right,deep)
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deep--//回溯
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}
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}
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```
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> 迭代法
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```go
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/**
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* Definition for a binary tree node.
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* type TreeNode struct {
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* Val int
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* Left *TreeNode
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* Right *TreeNode
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* }
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*/
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func findBottomLeftValue(root *TreeNode) int {
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queue:=list.New()
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var gradation int
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queue.PushBack(root)
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for queue.Len()>0{
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length:=queue.Len()
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for i:=0;i<length;i++{
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node:=queue.Remove(queue.Front()).(*TreeNode)
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if i==0{gradation=node.Val}
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if node.Left!=nil{
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queue.PushBack(node.Left)
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}
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if node.Right!=nil{
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queue.PushBack(node.Right)
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}
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}
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}
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return gradation
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}
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```
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JavaScript:
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1. 递归版本
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```javascript
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Reference in New Issue
Block a user