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Merge pull request #2173 from lifejwang11/master
修改java版本解法的位置,适合图的解法放在第一个,第二个解法(难理解版本)放在其后,新增java版本的迭代法
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@ -343,8 +343,32 @@ public:
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## 其他语言版本
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### Java
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### Java:
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未剪枝优化
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```java
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class Solution {
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List<List<Integer>> result= new ArrayList<>();
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LinkedList<Integer> path = new LinkedList<>();
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public List<List<Integer>> combine(int n, int k) {
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backtracking(n,k,1);
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return result;
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}
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public void backtracking(int n,int k,int startIndex){
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if (path.size() == k){
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result.add(new ArrayList<>(path));
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return;
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}
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for (int i =startIndex;i<=n;i++){
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path.add(i);
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backtracking(n,k,i+1);
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path.removeLast();
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}
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}
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}
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```
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剪枝优化:
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```java
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class Solution {
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List<List<Integer>> result = new ArrayList<>();
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@ -268,6 +268,34 @@ public:
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### Java
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```java
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// 解法1(最好理解的版本)
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class Solution {
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public TreeNode deleteNode(TreeNode root, int key) {
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if (root == null) return root;
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if (root.val == key) {
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if (root.left == null) {
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return root.right;
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} else if (root.right == null) {
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return root.left;
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} else {
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TreeNode cur = root.right;
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while (cur.left != null) {
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cur = cur.left;
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}
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cur.left = root.left;
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root = root.right;
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return root;
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}
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}
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if (root.val > key) root.left = deleteNode(root.left, key);
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if (root.val < key) root.right = deleteNode(root.right, key);
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return root;
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}
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}
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```
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```java
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class Solution {
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public TreeNode deleteNode(TreeNode root, int key) {
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@ -296,34 +324,59 @@ class Solution {
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}
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}
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```
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递归法
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```java
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// 解法2
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class Solution {
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public TreeNode deleteNode(TreeNode root, int key) {
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if (root == null) return root;
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if (root.val == key) {
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if (root.left == null) {
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return root.right;
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} else if (root.right == null) {
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return root.left;
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} else {
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TreeNode cur = root.right;
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while (cur.left != null) {
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cur = cur.left;
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}
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cur.left = root.left;
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root = root.right;
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return root;
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if (root == null){
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return null;
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}
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//寻找对应的对应的前面的节点,以及他的前一个节点
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TreeNode cur = root;
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TreeNode pre = null;
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while (cur != null){
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if (cur.val < key){
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pre = cur;
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cur = cur.right;
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} else if (cur.val > key) {
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pre = cur;
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cur = cur.left;
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}else {
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break;
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}
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}
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if (root.val > key) root.left = deleteNode(root.left, key);
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if (root.val < key) root.right = deleteNode(root.right, key);
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if (pre == null){
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return deleteOneNode(cur);
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}
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if (pre.left !=null && pre.left.val == key){
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pre.left = deleteOneNode(cur);
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}
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if (pre.right !=null && pre.right.val == key){
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pre.right = deleteOneNode(cur);
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}
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return root;
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}
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public TreeNode deleteOneNode(TreeNode node){
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if (node == null){
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return null;
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}
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if (node.right == null){
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return node.left;
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}
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TreeNode cur = node.right;
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while (cur.left !=null){
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cur = cur.left;
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}
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cur.left = node.left;
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return node.right;
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}
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}
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```
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### Python
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递归法(版本一)
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```python
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class Solution:
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