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添加 101. 对称二叉树 Swift版本
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@ -574,7 +574,87 @@ var isSymmetric = function(root) {
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};
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```
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## Swift:
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> 递归
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```swift
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func isSymmetric(_ root: TreeNode?) -> Bool {
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return _isSymmetric(root?.left, right: root?.right)
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}
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func _isSymmetric(_ left: TreeNode?, right: TreeNode?) -> Bool {
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// 首先排除空节点情况
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if left == nil && right == nil {
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return true
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} else if left == nil && right != nil {
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return false
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} else if left != nil && right == nil {
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return false
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} else if left!.val != right!.val {
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// 进而排除数值不相等的情况
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return false
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}
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// left 和 right 都不为空, 且数值也相等就递归
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let inSide = _isSymmetric(left!.right, right: right!.left)
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let outSide = _isSymmetric(left!.left, right: right!.right)
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return inSide && outSide
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}
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```
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> 迭代 - 使用队列
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```swift
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func isSymmetric2(_ root: TreeNode?) -> Bool {
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guard let root = root else {
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return true
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}
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var queue = [TreeNode?]()
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queue.append(root.left)
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queue.append(root.right)
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while !queue.isEmpty {
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let left = queue.removeFirst()
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let right = queue.removeFirst()
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if left == nil && right == nil {
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continue
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}
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if left == nil || right == nil || left?.val != right?.val {
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return false
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}
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queue.append(left!.left)
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queue.append(right!.right)
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queue.append(left!.right)
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queue.append(right!.left)
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}
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return true
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}
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```
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> 迭代 - 使用栈
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```swift
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func isSymmetric3(_ root: TreeNode?) -> Bool {
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guard let root = root else {
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return true
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}
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var stack = [TreeNode?]()
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stack.append(root.left)
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stack.append(root.right)
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while !stack.isEmpty {
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let left = stack.removeLast()
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let right = stack.removeLast()
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if left == nil && right == nil {
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continue
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}
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if left == nil || right == nil || left?.val != right?.val {
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return false
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}
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stack.append(left!.left)
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stack.append(right!.right)
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stack.append(left!.right)
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stack.append(right!.left)
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}
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return true
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}
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```
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-----------------------
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<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>
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