添加 1002.查找常用字符.md Python3 使用collections.Counter实现

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shuwen
2021-09-03 22:04:27 +08:00
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parent b8ef037a99
commit bcd03971db

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@ -193,6 +193,26 @@ class Solution:
hash[i] -= 1
return result
```
Python 3 使用collections.Counter
```python
class Solution:
def commonChars(self, words: List[str]) -> List[str]:
tmp = collections.Counter(words[0])
l = []
for i in range(1,len(words)):
# 使用 & 取交集
tmp = tmp & collections.Counter(words[i])
# 剩下的就是每个单词都出现的字符(键),个数(值)
for j in tmp:
v = tmp[j]
while(v):
l.append(j)
v -= 1
return l
```
javaScript
```js
var commonChars = function (words) {