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添加 1002.查找常用字符.md Python3 使用collections.Counter实现
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@ -193,6 +193,26 @@ class Solution:
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hash[i] -= 1
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return result
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```
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Python 3 使用collections.Counter
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```python
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class Solution:
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def commonChars(self, words: List[str]) -> List[str]:
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tmp = collections.Counter(words[0])
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l = []
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for i in range(1,len(words)):
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# 使用 & 取交集
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tmp = tmp & collections.Counter(words[i])
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# 剩下的就是每个单词都出现的字符(键),个数(值)
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for j in tmp:
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v = tmp[j]
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while(v):
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l.append(j)
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v -= 1
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return l
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```
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javaScript
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```js
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var commonChars = function (words) {
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