Merge pull request #103 from Joshua-Lu/patch-20

更新 0654.最大二叉树 Java版本
This commit is contained in:
Carl Sun
2021-05-14 10:30:49 +08:00
committed by GitHub

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@ -224,27 +224,32 @@ root->right = traversal(nums, maxValueIndex + 1, right);
Java
```java
```Java
class Solution {
public TreeNode constructMaximumBinaryTree(int[] nums) {
if (nums.length == 0) return null;
return constructMaximumBinaryTree(nums,0,nums.length);
return constructMaximumBinaryTree1(nums, 0, nums.length);
}
private TreeNode constructMaximumBinaryTree(int[] nums, int begin, int end) {
if (begin == end) return null;
int rootValue = nums[begin];
int index = begin;
for (int i = begin; i < end ; i++) {
if (nums[i] > rootValue) {
rootValue = nums[i];
index = i;
public TreeNode constructMaximumBinaryTree1(int[] nums, int leftIndex, int rightIndex) {
if (rightIndex - leftIndex < 1) {// 没有元素了
return null;
}
if (rightIndex - leftIndex == 1) {// 只有一个元素
return new TreeNode(nums[leftIndex]);
}
int maxIndex = leftIndex;// 最大值所在位置
int maxVal = nums[maxIndex];// 最大值
for (int i = leftIndex + 1; i < rightIndex; i++) {
if (nums[i] > maxVal){
maxVal = nums[i];
maxIndex = i;
}
}
TreeNode root = new TreeNode(rootValue);
root.left = constructMaximumBinaryTree(nums, begin,index);
root.right = constructMaximumBinaryTree(nums,index+1,end);
TreeNode root = new TreeNode(maxVal);
// 根据maxIndex划分左右子树
root.left = constructMaximumBinaryTree1(nums, leftIndex, maxIndex);
root.right = constructMaximumBinaryTree1(nums, maxIndex + 1, rightIndex);
return root;
}
}