Update 0513.找树左下角的值.md

This commit is contained in:
jianghongcheng
2023-05-06 01:55:48 -05:00
committed by GitHub
parent c4bc319750
commit b617532ce9

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@ -271,52 +271,80 @@ class Solution {
### Python
递归:
(版本一)递归法 + 回溯
```python
class Solution:
def findBottomLeftValue(self, root: TreeNode) -> int:
max_depth = -float("INF")
leftmost_val = 0
self.max_depth = float('-inf')
self.result = None
self.traversal(root, 0)
return self.result
def traversal(self, node, depth):
if not node.left and not node.right:
if depth > self.max_depth:
self.max_depth = depth
self.result = node.val
return
if node.left:
depth += 1
self.traversal(node.left, depth)
depth -= 1
if node.right:
depth += 1
self.traversal(node.right, depth)
depth -= 1
def __traverse(root, cur_depth):
nonlocal max_depth, leftmost_val
if not root.left and not root.right:
if cur_depth > max_depth:
max_depth = cur_depth
leftmost_val = root.val
if root.left:
cur_depth += 1
__traverse(root.left, cur_depth)
cur_depth -= 1
if root.right:
cur_depth += 1
__traverse(root.right, cur_depth)
cur_depth -= 1
__traverse(root, 0)
return leftmost_val
```
迭代 - 层序遍历:
(版本二)递归法+精简
```python
class Solution:
def findBottomLeftValue(self, root: TreeNode) -> int:
queue = deque()
if root:
queue.append(root)
result = 0
while queue:
q_len = len(queue)
for i in range(q_len):
if i == 0:
result = queue[i].val
cur = queue.popleft()
if cur.left:
queue.append(cur.left)
if cur.right:
queue.append(cur.right)
return result
self.max_depth = float('-inf')
self.result = None
self.traversal(root, 0)
return self.result
def traversal(self, node, depth):
if not node.left and not node.right:
if depth > self.max_depth:
self.max_depth = depth
self.result = node.val
return
if node.left:
self.traversal(node.left, depth+1)
if node.right:
self.traversal(node.right, depth+1)
```
(版本三) 迭代法
```python
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
from collections import deque
class Solution:
def findBottomLeftValue(self, root: Optional[TreeNode]) -> int:
queue = deque([root])
while queue:
size = len(queue)
leftmost = queue[0].val
for i in range(size):
node = queue.popleft()
if node.left:
queue.append(node.left)
if node.right:
queue.append(node.right)
if not queue:
return leftmost
```
### Go