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Merge pull request #2198 from fwqaaq/patch-51
Update 0115.不同的子序列.md about rust
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@ -314,6 +314,63 @@ function numDistinct(s: string, t: string): number {
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};
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```
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### Rust:
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```rust
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impl Solution {
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pub fn num_distinct(s: String, t: String) -> i32 {
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if s.len() < t.len() {
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return 0;
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}
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let mut dp = vec![vec![0; s.len() + 1]; t.len() + 1];
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// i = 0, t 为空字符串,s 作为子序列的个数为 1(删除 s 所有元素)
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dp[0] = vec![1; s.len() + 1];
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for (i, char_t) in t.chars().enumerate() {
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for (j, char_s) in s.chars().enumerate() {
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if char_t == char_s {
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// t 的前 i 个字符在 s 的前 j 个字符中作为子序列的个数
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dp[i + 1][j + 1] = dp[i][j] + dp[i + 1][j];
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continue;
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}
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dp[i + 1][j + 1] = dp[i + 1][j];
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}
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}
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dp[t.len()][s.len()]
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}
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}
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```
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> 滚动数组
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```rust
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impl Solution {
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pub fn num_distinct(s: String, t: String) -> i32 {
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if s.len() < t.len() {
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return 0;
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}
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let (s, t) = (s.into_bytes(), t.into_bytes());
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// 对于 t 为空字符串,s 作为子序列的个数为 1(删除 s 所有元素)
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let mut dp = vec![1; s.len() + 1];
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for char_t in t {
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// dp[i - 1][j - 1],dp[j + 1] 更新之前的值
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let mut pre = dp[0];
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// 当开始遍历 t,s 的前 0 个字符无法包含任意子序列
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dp[0] = 0;
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for (j, &char_s) in s.iter().enumerate() {
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let temp = dp[j + 1];
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if char_t == char_s {
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dp[j + 1] = pre + dp[j];
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} else {
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dp[j + 1] = dp[j];
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}
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pre = temp;
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}
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}
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dp[s.len()]
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}
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}
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```
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<p align="center">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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