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Update 剑指Offer05.替换空格.md
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@ -266,6 +266,7 @@ func replaceSpace(s string) string {
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python:
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####因为字符串是不可变类型,所以操作字符串需要将其转换为列表,因此空间复杂度不可能不为O(1)
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```python
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class Solution:
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def replaceSpace(self, s: str) -> str:
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