feat: 圖論101孤島总面积 ,新增python深搜算法

This commit is contained in:
suinming
2024-09-21 16:05:46 +08:00
parent 2bac133e1e
commit 99e85bfea1

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@ -307,6 +307,71 @@ for i in range(n):
print(count)
```
```python
direction = [[1, 0], [-1, 0], [0, 1], [0, -1]]
result = 0
# 深度搜尋
def dfs(grid, y, x):
grid[y][x] = 0
global result
result += 1
for i, j in direction:
next_x = x + j
next_y = y + i
if (next_x < 0 or next_y < 0 or
next_x >= len(grid[0]) or next_y >= len(grid)
):
continue
if grid[next_y][next_x] == 1 and not visited[next_y][next_x]:
visited[next_y][next_x] = True
dfs(grid, next_y, next_x)
# 讀取輸入值
n, m = map(int, input().split())
grid = []
visited = [[False] * m for _ in range(n)]
for i in range(n):
grid.append(list(map(int, input().split())))
# 處理邊界
for j in range(m):
# 上邊界
if grid[0][j] == 1 and not visited[0][j]:
visited[0][j] = True
dfs(grid, 0, j)
# 下邊界
if grid[n - 1][j] == 1 and not visited[n - 1][j]:
visited[n - 1][j] = True
dfs(grid, n - 1, j)
for i in range(n):
# 左邊界
if grid[i][0] == 1 and not visited[i][0]:
visited[i][0] = True
dfs(grid, i, 0)
# 右邊界
if grid[i][m - 1] == 1 and not visited[i][m - 1]:
visited[i][m - 1] = True
dfs(grid, i, m - 1)
# 計算孤島總面積
result = 0 # 初始化,避免使用到處理邊界時所產生的累加值
for i in range(n):
for j in range(m):
if grid[i][j] == 1 and not visited[i][j]:
visited[i][j] = True
dfs(grid, i, j)
# 輸出孤島的總面積
print(result)
```
### Go
``` go