update 0383.赎金信: 完善注释

problems/0383.赎金信.md

@@ -147,11 +147,11 @@ class Solution:
 
         arr = [0] * 26
 
-        for x in magazine:
+        for x in magazine:    # 记录 magazine里各个字符出现次数
             arr[ord(x) - ord('a')] += 1
 
-        for x in ransomNote:
-            if arr[ord(x) - ord('a')] == 0:
+        for x in ransomNote:  # 在arr里对应的字符个数做--操作
+            if arr[ord(x) - ord('a')] == 0:  # 如果没有出现过直接返回
                 return False
             else:
                 arr[ord(x) - ord('a')] -= 1
@@ -234,12 +234,12 @@ Go：
 ```go
 func canConstruct(ransomNote string, magazine string) bool {
     record := make([]int, 26)
-    for _, v := range magazine {
+    for _, v := range magazine {   // 通过recode数据记录 magazine里各个字符出现次数
         record[v-'a']++
     }
-    for _, v := range ransomNote {
+    for _, v := range ransomNote { // 遍历ransomNote，在record里对应的字符个数做--操作
         record[v-'a']--
-        if record[v-'a'] < 0 {
+        if record[v-'a'] < 0 {     // 如果小于零说明ransomNote里出现的字符，magazine没有
             return false
         }
     }
@@ -258,12 +258,12 @@ javaScript:
 var canConstruct = function(ransomNote, magazine) {
     const strArr = new Array(26).fill(0), 
         base = "a".charCodeAt();
-    for(const s of magazine) {
+    for(const s of magazine) {  // 记录 magazine里各个字符出现次数
         strArr[s.charCodeAt() - base]++;
     }
-    for(const s of ransomNote) {
+    for(const s of ransomNote) { // 对应的字符个数做--操作
         const index = s.charCodeAt() - base;
-        if(!strArr[index]) return false;
+        if(!strArr[index]) return false;  // 如果没记录过直接返回false
         strArr[index]--;
     }
     return true;