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Merge pull request #151 from csresource04/master

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更新0035.搜索插入位置  0257.二叉树的所有路径  Markdown代码块语法
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Carl Sun
2021-05-16 21:21:23 +08:00
committed by GitHub
parent a735216a0b 21a4b9d64b
commit 97900c9460
2 changed files with 6 additions and 6 deletions
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4
problems/0035.搜索插入位置.md
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@ -116,7 +116,7 @@ public:
**大家要仔细看注释，思考为什么要写while(left <= right)， 为什么要写right = middle - 1**。
```
```C++
class Solution {
public:
int searchInsert(vector<int>& nums, int target) {
@ -158,7 +158,7 @@ public:
**大家要仔细看注释，思考为什么要写while (left < right)， 为什么要写right = middle**。
```
```C++
class Solution {
public:
int searchInsert(vector<int>& nums, int target) {

8
problems/0257.二叉树的所有路径.md
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@ -77,7 +77,7 @@ if (cur->left == NULL && cur->right == NULL) {
这里我们先使用vector<int>结构的path容器来记录路径，那么终止处理逻辑如下：
```
```C++
if (cur->left == NULL && cur->right == NULL) { // 遇到叶子节点
string sPath;
for (int i = 0; i < path.size() - 1; i++) { // 将path里记录的路径转为string格式
@ -113,7 +113,7 @@ if (cur->right) {
那么回溯要怎么回溯呢，一些同学会这么写，如下：
```
```C++
if (cur->left) {
traversal(cur->left, path, result);
}
@ -129,7 +129,7 @@ path.pop_back();
那么代码应该这么写：
```
```C++
if (cur->left) {
traversal(cur->left, path, result);
path.pop_back(); // 回溯
@ -335,4 +335,4 @@ Go：
* 作者微信：[程序员Carl](https://mp.weixin.qq.com/s/b66DFkOp8OOxdZC_xLZxfw)
* B站视频：[代码随想录](https://space.bilibili.com/525438321)
* 知识星球：[代码随想录](https://mp.weixin.qq.com/s/QVF6upVMSbgvZy8lHZS3CQ)
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