Update 0922.按奇偶排序数组Ⅱ.md 添加了Java版本的两种方法

problems/0922.按奇偶排序数组II.md

@@ -147,6 +147,59 @@ class Solution {
 }
 ```
 
+### java
+
+```java
+//方法一：采用额外的数组空间
+class Solution {
+    public int[] sortArrayByParityII(int[] nums) {
+        //定义结果数组 result
+        int[] result = new int[nums.length];
+        int even = 0, odd = 1;
+        for(int i = 0; i < nums.length; i++){
+            //如果为偶数
+            if(nums[i] % 2 == 0){
+                result[even] = nums[i];
+                even += 2;
+            }else{
+                result[odd] = nums[i];
+                odd += 2;
+            }
+        }
+        return result;
+    }
+}
+```
+```java
+//方法二：不采用额外的数组空间
+class Solution922 {
+    public int[] sortArrayByParityII(int[] nums) {
+        //定义双指针
+        int oddPoint = 1, evenPoint = 0;
+        //开始移动并交换，最后一层必然为相互交换后再移动或者相同直接移动
+        while(oddPoint < nums.length && evenPoint < nums.length){
+            //进行判断
+            if(nums[oddPoint] % 2 == 0 && nums[evenPoint] % 2 == 1){    //如果均不满足
+                int temp = 0;
+                temp = nums[oddPoint];
+                nums[oddPoint] = nums[evenPoint];
+                nums[evenPoint] = temp;
+                oddPoint += 2;
+                evenPoint += 2;
+            }else if(nums[oddPoint] % 2 == 0 && nums[evenPoint] % 2 == 0){  //偶数满足
+                evenPoint += 2;
+            }else if(nums[oddPoint] % 2 == 1 && nums[evenPoint] % 2 == 1){  //奇数满足
+                oddPoint += 2;
+            }else{
+                oddPoint += 2;
+                evenPoint += 2;
+            }
+        }
+        return nums;
+    }
+}
+```
+
 ### Python3
 
 ```python