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更新 面试题02.07.链表相交 错别字勘误

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2021-10-25 10:38:34 +08:00
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problems/面试题02.07.链表相交.md
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@ -38,7 +38,7 @@
![面试题02.07.链表相交_2](https://code-thinking.cdn.bcebos.com/pics/面试题02.07.链表相交_2.png)
此时我们就可以比较curA和curB是否相同，如果不相同，同时向后移动curA和curB，如果遇到curA == curB，则找到焦点。
此时我们就可以比较curA和curB是否相同，如果不相同，同时向后移动curA和curB，如果遇到curA == curB，则找到交点。
否则循环退出返回空指针。