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update 0053.最大子序和:添加复杂度分析
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@ -24,8 +24,6 @@
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暴力解法的思路,第一层 for 就是设置起始位置,第二层 for 循环遍历数组寻找最大值
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- 时间复杂度:O(n^2)
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- 空间复杂度:O(1)
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```CPP
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class Solution {
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@ -44,6 +42,9 @@ public:
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}
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};
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```
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* 时间复杂度:O(n^2)
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* 空间复杂度:O(1)
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以上暴力的解法 C++勉强可以过,其他语言就不确定了。
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@ -98,7 +99,6 @@ public:
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}
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};
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```
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- 时间复杂度:O(n)
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- 空间复杂度:O(1)
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