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Add 0209.长度最小的子数组.md C语言解法

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Guanzhong Pan
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problems/0209.长度最小的子数组.md
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@ -330,5 +330,55 @@ def min_sub_array_len(target, nums)
end
```
C:
暴力解法:
```c
int minSubArrayLen(int target, int* nums, int numsSize){
//初始化最小长度为INT_MAX
int minLength = INT_MAX;
int sum;
int left, right;
for(left = 0; left < numsSize; ++left) {
//每次遍历都清零sum，计算当前位置后和>=target的子数组的长度
sum = 0;
//从left开始，sum中添加元素
for(right = left; right < numsSize; ++right) {
sum += nums[right];
//若加入当前元素后，和大于target，则更新minLength
if(sum >= target) {
int subLength = right - left + 1;
minLength = minLength < subLength ? minLength : subLength;
}
}
}
//若minLength不为INT_MAX，则返回minLnegth
return minLength == INT_MAX ? 0 : minLength;
}
```
滑动窗口:
```c
int minSubArrayLen(int target, int* nums, int numsSize){
//初始化最小长度为INT_MAX
int minLength = INT_MAX;
int sum = 0;
int left = 0, right = 0;
//右边界向右扩展
for(; right < numsSize; ++right) {
sum += nums[right];
//当sum的值大于等于target时，保存长度，并且收缩左边界
while(sum >= target) {
int subLength = right - left + 1;
minLength = minLength < subLength ? minLength : subLength;
sum -= nums[left++];
}
}
//若minLength不为INT_MAX，则返回minLnegth
return minLength == INT_MAX ? 0 : minLength;
}
```
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