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Merge pull request #1416 from wzqwtt/tree15
添加(0236.二叉树的最近公共祖先、0235.二叉搜索树的最近公共祖先) Scala版本
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@ -381,7 +381,36 @@ function lowestCommonAncestor(root: TreeNode | null, p: TreeNode | null, q: Tree
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};
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```
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## Scala
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递归:
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```scala
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object Solution {
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def lowestCommonAncestor(root: TreeNode, p: TreeNode, q: TreeNode): TreeNode = {
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// scala中每个关键字都有其返回值,于是可以不写return
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if (root.value > p.value && root.value > q.value) lowestCommonAncestor(root.left, p, q)
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else if (root.value < p.value && root.value < q.value) lowestCommonAncestor(root.right, p, q)
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else root
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}
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}
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```
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迭代:
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```scala
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object Solution {
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def lowestCommonAncestor(root: TreeNode, p: TreeNode, q: TreeNode): TreeNode = {
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var curNode = root // 因为root是不可变量,所以要赋值给curNode一个可变量
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while(curNode != null){
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if(curNode.value > p.value && curNode.value > q.value) curNode = curNode.left
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else if(curNode.value < p.value && curNode.value < q.value) curNode = curNode.right
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else return curNode
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}
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null
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}
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}
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```
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-----------------------
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@ -343,7 +343,25 @@ function lowestCommonAncestor(root: TreeNode | null, p: TreeNode | null, q: Tree
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};
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```
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## Scala
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```scala
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object Solution {
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def lowestCommonAncestor(root: TreeNode, p: TreeNode, q: TreeNode): TreeNode = {
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// 递归结束条件
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if (root == null || root == p || root == q) {
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return root
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}
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var left = lowestCommonAncestor(root.left, p, q)
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var right = lowestCommonAncestor(root.right, p, q)
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if (left != null && right != null) return root
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if (left == null) return right
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left
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}
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}
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```
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-----------------------
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<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>
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