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更新0213.打家劫舍II.md 更简洁的python 版本
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@ -123,22 +123,24 @@ Python:
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```Python
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class Solution:
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def rob(self, nums: List[int]) -> int:
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if (n := len(nums)) == 0:
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return 0
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if n == 1:
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return nums[0]
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result1 = self.robRange(nums, 0, n - 2)
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result2 = self.robRange(nums, 1, n - 1)
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return max(result1 , result2)
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#在198入门级的打家劫舍问题上分两种情况考虑
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#一是不偷第一间房,二是不偷最后一间房
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if len(nums)==1:#题目中提示nums.length>=1,所以不需要考虑len(nums)==0的情况
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return nums[0]
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val1=self.roblist(nums[1:])#不偷第一间房
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val2=self.roblist(nums[:-1])#不偷最后一间房
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return max(val1,val2)
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def robRange(self, nums: List[int], start: int, end: int) -> int:
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if end == start: return nums[start]
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dp = [0] * len(nums)
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dp[start] = nums[start]
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dp[start + 1] = max(nums[start], nums[start + 1])
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for i in range(start + 2, end + 1):
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dp[i] = max(dp[i -2] + nums[i], dp[i - 1])
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return dp[end]
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def robRange(self,nums):
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l=len(nums)
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dp=[0]*l
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dp[0]=nums[0]
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for i in range(1,l):
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if i==1:
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dp[i]=max(dp[i-1],nums[i])
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else:
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dp[i]=max(dp[i-1],dp[i-2]+nums[i])
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return dp[-1]
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```
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javascipt:
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