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按照解题思路优化代码及变量名称
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@ -138,42 +138,51 @@ public:
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```Java
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class Solution {
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public int[][] generateMatrix(int n) {
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int loop = 0; // 控制循环次数
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int[][] res = new int[n][n];
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int start = 0; // 每次循环的开始点(start, start)
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int count = 1; // 定义填充数字
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int i, j;
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int[][] nums = new int[n][n];
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int startX = 0, startY = 0; // 每一圈的起始点
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int offset = 1;
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int count = 1; // 矩阵中需要填写的数字
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int loop = 1; // 记录当前的圈数
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int i, j; // j 代表列, i 代表行;
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while (loop++ < n / 2) { // 判断边界后,loop从1开始
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// 模拟上侧从左到右
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for (j = start; j < n - loop; j++) {
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res[start][j] = count++;
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while (loop <= n / 2) {
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// 顶部
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// 左闭右开,所以判断循环结束时, j 不能等于 n - offset
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for (j = startY; j < n - offset; j++) {
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nums[startX][j] = count++;
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}
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// 模拟右侧从上到下
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for (i = start; i < n - loop; i++) {
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res[i][j] = count++;
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// 右列
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// 左闭右开,所以判断循环结束时, i 不能等于 n - offset
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for (i = startX; i < n - offset; i++) {
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nums[i][j] = count++;
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}
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// 模拟下侧从右到左
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for (; j >= loop; j--) {
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res[i][j] = count++;
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// 底部
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// 左闭右开,所以判断循环结束时, j != startY
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for (; j > startY; j--) {
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nums[i][j] = count++;
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}
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// 模拟左侧从下到上
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for (; i >= loop; i--) {
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res[i][j] = count++;
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// 左列
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// 左闭右开,所以判断循环结束时, i != startX
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for (; i > startX; i--) {
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nums[i][j] = count++;
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}
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start++;
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startX++;
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startY++;
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offset++;
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loop++;
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}
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if (n % 2 == 1) {
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res[start][start] = count;
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if (n % 2 == 1) { // n 为奇数时,单独处理矩阵中心的值
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nums[startX][startY] = count;
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}
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return res;
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return nums;
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}
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}
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```
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### python3:
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