Merge pull request #1547 from firemaples/patch-1

Update 0452.用最少数量的箭引爆气球.md
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程序员Carl
2022-08-10 10:06:04 +08:00
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@ -150,6 +150,7 @@ class Solution {
int count = 1;
//重叠气球的最小右边界
int leftmostRightBound = points[0][1];
for (int i = 1; i < points.length; i++) {
//如果下一个气球的左边界大于最小右边界
for(int i = 1; i < points.length; i++){
if (points[i][0] > leftmostRightBound ) {