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Merge pull request #845 from Jerry-306/patch-36
添加 1207 独一无二的出现次数 JavaScript版本 使用哈希表和集合的解法
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@ -119,6 +119,7 @@ Go:
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JavaScript:
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``` javascript
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// 方法一:使用数组记录元素出现次数
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var uniqueOccurrences = function(arr) {
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const count = new Array(2002).fill(0);// -1000 <= arr[i] <= 1000
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for(let i = 0; i < arr.length; i++){
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@ -134,6 +135,21 @@ var uniqueOccurrences = function(arr) {
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}
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return true;
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};
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// 方法二:使用Map 和 Set
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/**
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* @param {number[]} arr
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* @return {boolean}
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*/
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var uniqueOccurrences = function(arr) {
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// 记录每个元素出现次数
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let map = new Map();
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arr.forEach( x => {
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map.set(x, (map.get(x) || 0) + 1);
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})
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// Set() 里的元素是不重复的。如果有元素出现次数相同,则最后的set的长度不等于map的长度
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return map.size === new Set(map.values()).size
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};
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```
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-----------------------
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