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922. 按奇偶排序数组II 添加Java版本
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@ -120,6 +120,31 @@ public:
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## Java
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```java
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// 方法一
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class Solution {
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public int[] sortArrayByParityII(int[] nums) {
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// 分别存放 nums 中的奇数、偶数
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int len = nums.length;
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int evenIndex = 0;
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int oddIndex = 0;
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int[] even = new int[len / 2];
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int[] odd = new int[len / 2];
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for (int i = 0; i < len; i++) {
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if (nums[i] % 2 == 0) {
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even[evenIndex++] = nums[i];
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} else {
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odd[oddIndex++] = nums[i];
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}
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}
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// 把奇偶数组重新存回 nums
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int index = 0;
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for (int i = 0; i < even.length; i++) {
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nums[index++] = even[i];
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nums[index++] = odd[i];
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}
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return nums;
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}
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}
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```
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## Python
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@ -143,4 +168,3 @@ public:
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* 知识星球:[代码随想录](https://mp.weixin.qq.com/s/QVF6upVMSbgvZy8lHZS3CQ)
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<div align="center"><img src=../pics/公众号.png width=450 alt=> </img></div>
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