Merge pull request #2447 from lynndove/master

827.最大人工岛 添加go解法
This commit is contained in:
程序员Carl
2024-02-28 14:30:39 +08:00
committed by GitHub

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@ -348,6 +348,99 @@ class Solution:
```
### Go
```go
func largestIsland(grid [][]int) int {
dir := [][]int{{0, 1}, {1, 0}, {-1, 0}, {0, -1}}
n := len(grid)
m := len(grid[0])
area := 0
visited := make([][]bool, n)
for i := 0; i < n; i++ {
visited[i] = make([]bool, m)
}
gridNum := make(map[int]int, 0) // 记录每一个岛屿的面积
mark := 2 // 记录每个岛屿的编号
isAllGrid := true
res := 0 // 标记是否整个地图都是陆地
var dfs func(grid [][]int, visited [][]bool, x, y, mark int)
dfs = func(grid [][]int, visited [][]bool, x, y, mark int) {
// 终止条件:访问过的节点 或者 遇到海水
if visited[x][y] || grid[x][y] == 0 {
return
}
visited[x][y] = true // 标记访问过
grid[x][y] = mark // 给陆地标记新标签
area++
for i := 0; i < 4; i++ {
nextX := x + dir[i][0]
nextY := y + dir[i][1]
if nextX < 0 || nextX >= len(grid) || nextY < 0 || nextY >= len(grid[0]) {
continue
}
dfs(grid, visited, nextX, nextY, mark)
}
}
for i := 0; i < n; i++ {
for j := 0; j < m; j++ {
if grid[i][j] == 0 {
isAllGrid = false
}
if !visited[i][j] && grid[i][j] == 1 {
area = 0
dfs(grid, visited, i, j, mark) // 将与其链接的陆地都标记上 true
gridNum[mark] = area // 记录每一个岛屿的面积
mark++ // 更新下一个岛屿编号
}
}
}
if isAllGrid {
return n * m
}
// 根据添加陆地的位置,计算周边岛屿面积之和
visitedGrid := make(map[int]struct{}) // 标记访问过的岛屿
for i := 0; i < n; i++ {
for j := 0; j < m; j++ {
count := 1 // 记录连接之后的岛屿数量
visitedGrid = make(map[int]struct{}) // 每次使用时,清空
if grid[i][j] == 0 {
for k := 0; k < 4; k++ {
// 计算相邻坐标
nearI := i + dir[k][0]
nearJ := j + dir[k][1]
if nearI < 0 || nearI >= len(grid) || nearJ < 0 || nearJ >= len(grid[0]) {
continue
}
// 添加过的岛屿不要重复添加
if _, ok := visitedGrid[grid[nearI][nearJ]]; ok {
continue
}
// 把相邻四面的岛屿数量加起来
count += gridNum[grid[nearI][nearJ]]
// 标记该岛屿已经添加过
visitedGrid[grid[nearI][nearJ]] = struct{}{}
}
}
res = max827(res, count)
}
}
return res
}
func max827(x, y int) int {
if x > y {
return x
}
return y
}
```
### JavaScript
```JavaScript
@ -411,8 +504,6 @@ return res;
```
<p align="center">
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