Merge pull request #2289 from aFlyBird0/batch-1

改写两处Go代码,使其更符合Go习惯
This commit is contained in:
程序员Carl
2023-10-05 09:58:59 +08:00
committed by GitHub
2 changed files with 42 additions and 43 deletions

View File

@ -225,32 +225,38 @@ class Solution:
// 打家劫舍Ⅱ 动态规划 // 打家劫舍Ⅱ 动态规划
// 时间复杂度O(n) 空间复杂度O(n) // 时间复杂度O(n) 空间复杂度O(n)
func rob(nums []int) int { func rob(nums []int) int {
if len(nums) == 1 { // 如果长度为0或1那么有没有环的限制都一样
return nums[0] if len(nums) <= 1 {
return robWithoutCircle(nums)
} }
if len(nums) == 2 {
return max(nums[0], nums[1]) // 否则,去头或去尾,取最大
} res1 := robWithoutCircle(nums[:len(nums)-1])
res2 := robWithoutCircle(nums[1:])
result1 := robRange(nums, 0)
result2 := robRange(nums, 1) return max(res1, res2)
return max(result1, result2)
} }
// 偷盗指定的范围 // 原始的打家劫舍版
func robRange(nums []int, start int) int { func robWithoutCircle(nums []int) int {
switch len(nums) {
case 0: return 0
case 1: return nums[0]
}
dp := make([]int, len(nums)) dp := make([]int, len(nums))
dp[1] = nums[start] dp[0]=nums[0]
dp[1] = max(nums[0], nums[1])
for i := 2; i < len(nums); i++ {
dp[i] = max(dp[i - 2] + nums[i - 1 + start], dp[i - 1]) for i:=2; i<len(nums); i++ {
dp[i] = max(dp[i-1], dp[i-2]+nums[i])
} }
return dp[len(nums) - 1] return dp[len(nums)-1]
} }
func max(a, b int) int { func max(a, b int ) int {
if a > b { if a>b {
return a return a
} }
return b return b

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@ -171,36 +171,29 @@ class Solution:
```go ```go
func sortByBits(arr []int) []int { func sortByBits(arr []int) []int {
var tmp int // 是否arr[i]<=arr[j]
for i := 0; i < len(arr); i++ { // 先比较1的数量后比较值本身
for j := i+1; j < len(arr); j++ { cmp := func(i, j int) bool {
// 冒泡排序的手法但是排序的规则从比大小变成了比位运算1的个数 c1, c2 := bitCount(arr[i]), bitCount(arr[j])
if isCmp(arr[i], arr[j]) { if c1 == c2 {
tmp = arr[i] return arr[i] <= arr[j]
arr[i] = arr[j] }
arr[j] = tmp return c1 <= c2
}
}
} }
// 调用库函数
// 第一个参数是待排序切片第二个是第i位是否小于第j位的函数
sort.Slice(arr, cmp)
return arr return arr
} }
func isCmp(a, b int) bool { func bitCount(num int) (count int) {
bitA := bitCount(a) for num != 0 {
bitB := bitCount(b) num &= num-1 // 每次运算将最右侧的1变成0
if bitA == bitB {
return a > b
} else {
return bitA > bitB
}
}
func bitCount(n int) int {
count := 0
for n != 0 {
n &= (n-1) // 清除最低位的1
count++ count++
} }
return count return count
} }
``` ```