mirror of
https://github.com/youngyangyang04/leetcode-master.git
synced 2025-07-08 00:43:04 +08:00
@ -346,69 +346,56 @@ class Solution {
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### Go
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```Go
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import "strings"
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var res [][]string
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func isValid(board [][]string, row, col int) (res bool){
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n := len(board)
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for i:=0; i < row; i++ {
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if board[i][col] == "Q" {
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return false
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}
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}
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for i := 0; i < n; i++{
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if board[row][i] == "Q" {
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return false
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}
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}
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for i ,j := row, col; i >= 0 && j >=0 ; i, j = i - 1, j- 1{
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if board[i][j] == "Q"{
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return false
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}
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}
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for i, j := row, col; i >=0 && j < n; i,j = i-1, j+1 {
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if board[i][j] == "Q" {
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return false
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}
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}
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return true
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}
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func backtrack(board [][]string, row int) {
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size := len(board)
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if row == size{
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temp := make([]string, size)
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for i := 0; i<size;i++{
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temp[i] = strings.Join(board[i],"")
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}
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res =append(res,temp)
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return
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}
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for col := 0; col < size; col++ {
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if !isValid(board, row, col){
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continue
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}
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board[row][col] = "Q"
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backtrack(board, row+1)
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board[row][col] = "."
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}
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}
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func solveNQueens(n int) [][]string {
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res = [][]string{}
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board := make([][]string, n)
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for i := 0; i < n; i++{
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board[i] = make([]string, n)
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}
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for i := 0; i < n; i++{
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for j := 0; j<n;j++{
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board[i][j] = "."
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}
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}
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backtrack(board, 0)
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var res [][]string
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chessboard := make([][]string, n)
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for i := 0; i < n; i++ {
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chessboard[i] = make([]string, n)
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}
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for i := 0; i < n; i++ {
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for j := 0; j < n; j++ {
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chessboard[i][j] = "."
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}
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}
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var backtrack func(int)
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backtrack = func(row int) {
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if row == n {
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temp := make([]string, n)
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for i, rowStr := range chessboard {
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temp[i] = strings.Join(rowStr, "")
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}
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res = append(res, temp)
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return
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}
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for i := 0; i < n; i++ {
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if isValid(n, row, i, chessboard) {
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chessboard[row][i] = "Q"
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backtrack(row + 1)
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chessboard[row][i] = "."
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}
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}
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}
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backtrack(0)
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return res
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}
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return res
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func isValid(n, row, col int, chessboard [][]string) bool {
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for i := 0; i < row; i++ {
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if chessboard[i][col] == "Q" {
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return false
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}
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}
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for i, j := row-1, col-1; i >= 0 && j >= 0; i, j = i-1, j-1 {
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if chessboard[i][j] == "Q" {
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return false
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}
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}
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for i, j := row-1, col+1; i >= 0 && j < n; i, j = i-1, j+1 {
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if chessboard[i][j] == "Q" {
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return false
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}
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}
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return true
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}
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```
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### Javascript
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@ -266,46 +266,33 @@ Go:
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```go
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func uniquePathsWithObstacles(obstacleGrid [][]int) int {
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m,n:= len(obstacleGrid),len(obstacleGrid[0])
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m, n := len(obstacleGrid), len(obstacleGrid[0])
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// 定义一个dp数组
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dp := make([][]int,m)
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for i,_ := range dp {
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dp[i] = make([]int,n)
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dp := make([][]int, m)
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for i, _ := range dp {
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dp[i] = make([]int, n)
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}
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// 初始化
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for i:=0;i<m;i++ {
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// 如果是障碍物, 后面的就都是0, 不用循环了
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if obstacleGrid[i][0] == 1 {
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break
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}
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dp[i][0]=1
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// 初始化, 如果是障碍物, 后面的就都是0, 不用循环了
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for i := 0; i < m && obstacleGrid[i][0] == 0; i++ {
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dp[i][0] = 1
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}
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for i:=0;i<n;i++ {
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if obstacleGrid[0][i] == 1 {
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break
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}
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dp[0][i]=1
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for i := 0; i < n && obstacleGrid[0][i] == 0; i++ {
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dp[0][i] = 1
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}
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// dp数组推导过程
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for i:=1;i<m;i++ {
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for j:=1;j<n;j++ {
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// 如果obstacleGrid[i][j]这个点是障碍物, 那么我们的dp[i][j]保持为0
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if obstacleGrid[i][j] != 1 {
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for i := 1; i < m; i++ {
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for j := 1; j < n; j++ {
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// 如果obstacleGrid[i][j]这个点是障碍物, 那么dp[i][j]保持为0
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if obstacleGrid[i][j] != 1 {
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// 否则我们需要计算当前点可以到达的路径数
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dp[i][j] = dp[i-1][j]+dp[i][j-1]
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dp[i][j] = dp[i-1][j] + dp[i][j-1]
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}
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}
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}
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// debug遍历dp
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//for i,_ := range dp {
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// for j,_ := range dp[i] {
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// fmt.Printf("%.2v,",dp[i][j])
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// }
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// fmt.Println()
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//}
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return dp[m-1][n-1]
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}
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```
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Javascript
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@ -289,7 +289,7 @@ func findTargetSumWays(nums []int, target int) int {
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for _, v := range nums {
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sum += v
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}
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if target > sum {
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if abs(target) > sum {
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return 0
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}
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if (sum+target)%2 == 1 {
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@ -311,49 +311,12 @@ func findTargetSumWays(nums []int, target int) int {
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}
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return dp[bag]
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}
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```
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> 更新版,上一个跑不通了,因为会存在bag 小于0的情况
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```go
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func findTargetSumWays(nums []int, target int) int {
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//先转化为数学问题
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//a-b=target
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//a+b=sum
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//a=(target+sum)/2
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//求出sum
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var sum int
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for _,value:=range nums{
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sum+=value
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}
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//如果sum<target或者 sum+target不是偶数(因为a是int) 或者两者之和小于0了
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if sum<target||(sum+target)%2==1||(sum+target)<0{
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return 0
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}
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//开始dp初始化
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dp:=make([][]int,len(nums)+1)
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for i:=0;i<=len(nums);i++{
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tmp:=make([]int,(target+sum)/2+1)//背包容量
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dp[i]=tmp
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}
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dp[0][0]=1//当背包容量为0,且物品为0时,填满背包就1种方法
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for i:=0;i<len(nums)+1;i++{
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if i==0{
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continue
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}
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for j:=0;j<(target+sum)/2+1;j++{
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if nums[i-1]<=j{//如果背包装的下
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dp[i][j]=dp[i-1][j]+dp[i-1][j-nums[i-1]]
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}else{
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dp[i][j]=dp[i-1][j]
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}
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}
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}
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return dp[len(nums)][(target+sum)/2]
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func abs(x int) int {
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return int(math.Abs(float64(x)))
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}
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```
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Javascript:
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```javascript
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const findTargetSumWays = (nums, target) => {
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Reference in New Issue
Block a user