添加 1002. 查找常用字符 Swift版本

This commit is contained in:
极客学伟
2021-08-31 13:02:33 +08:00
parent 513ccbc51b
commit 29876fbdee

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@ -268,6 +268,47 @@ func min(a,b int)int{
return a
}
```
Swift
```swift
func commonChars(_ words: [String]) -> [String] {
var res = [String]()
if words.count < 1 {
return res
}
let aUnicodeScalarValue = "a".unicodeScalars.first!.value
let lettersMaxCount = 26
// 用于统计所有字符串每个字母出现的 最小 频率
var hash = Array(repeating: 0, count: lettersMaxCount)
// 统计第一个字符串每个字母出现的次数
for unicodeScalar in words.first!.unicodeScalars {
hash[Int(unicodeScalar.value - aUnicodeScalarValue)] += 1
}
// 统计除第一个字符串每个字母出现的次数
for idx in 1 ..< words.count {
var hashOtherStr = Array(repeating: 0, count: lettersMaxCount)
for unicodeScalar in words[idx].unicodeScalars {
hashOtherStr[Int(unicodeScalar.value - aUnicodeScalarValue)] += 1
}
// 更新hash,保证hash里统计的字母为出现的最小频率
for k in 0 ..< lettersMaxCount {
hash[k] = min(hash[k], hashOtherStr[k])
}
}
// 将hash统计的字符次数转成输出形式
for i in 0 ..< lettersMaxCount {
while hash[i] != 0 { // 注意这里是while多个重复的字符
let currentUnicodeScalarValue: UInt32 = UInt32(i) + aUnicodeScalarValue
let currentUnicodeScalar: UnicodeScalar = UnicodeScalar(currentUnicodeScalarValue)!
let outputStr = String(currentUnicodeScalar) // UnicodeScalar -> String
res.append(outputStr)
hash[i] -= 1
}
}
return res
}
```
-----------------------
* 作者微信:[程序员Carl](https://mp.weixin.qq.com/s/b66DFkOp8OOxdZC_xLZxfw)
* B站视频[代码随想录](https://space.bilibili.com/525438321)