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Merge branch 'youngyangyang04:master' into leetcode-modify-the-code-of-the-BinaryTree

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Yuhao Ju
2022-12-05 10:19:55 +08:00
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parent b93d9f6d89 7477960034
commit 2835ac55c7
6 changed files with 301 additions and 8 deletions
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105
problems/0112.路径总和.md
View File

@ -1219,6 +1219,111 @@ object Solution {
}
```
## rust
### 112.路径总和.md
递归：
```rust
use std::rc::Rc;
use std::cell::RefCell;
impl Solution {
pub fn has_path_sum(root: Option<Rc<RefCell<TreeNode>>>, target_sum: i32) -> bool {
if root.is_none() {
return false;
}
let node = root.unwrap();
if node.borrow().left.is_none() && node.borrow().right.is_none() {
return node.borrow().val == target_sum;
}
return Self::has_path_sum(node.borrow().left.clone(), target_sum - node.borrow().val)
|| Self::has_path_sum(node.borrow().right.clone(), target_sum - node.borrow().val);
}
}
```
迭代：
```rust
use std::rc::Rc;
use std::cell::RefCell;
impl Solution {
pub fn has_path_sum(root: Option<Rc<RefCell<TreeNode>>>, target_sum: i32) -> bool {
let mut stack = vec![];
if let Some(node) = root {
stack.push((node.borrow().val, node.to_owned()));
}
while !stack.is_empty() {
let (value, node) = stack.pop().unwrap();
if node.borrow().left.is_none() && node.borrow().right.is_none() && value == target_sum
{
return true;
}
if node.borrow().left.is_some() {
if let Some(r) = node.borrow().left.as_ref() {
stack.push((r.borrow().val + value, r.to_owned()));
}
}
if node.borrow().right.is_some() {
if let Some(r) = node.borrow().right.as_ref() {
stack.push((r.borrow().val + value, r.to_owned()));
}
}
}
false
}
```
### 113.路径总和-ii
```rust
impl Solution {
pub fn path_sum(root: Option<Rc<RefCell<TreeNode>>>, target_sum: i32) -> Vec<Vec<i32>> {
let mut res = vec![];
let mut route = vec![];
if root.is_none() {
return res;
} else {
route.push(root.as_ref().unwrap().borrow().val);
}
Self::recur(
&root,
target_sum - root.as_ref().unwrap().borrow().val,
&mut res,
&mut route,
);
res
}
pub fn recur(
root: &Option<Rc<RefCell<TreeNode>>>,
sum: i32,
res: &mut Vec<Vec<i32>>,
route: &mut Vec<i32>,
) {
let node = root.as_ref().unwrap().borrow();
if node.left.is_none() && node.right.is_none() && sum == 0 {
res.push(route.to_vec());
return;
}
if node.left.is_some() {
let left = node.left.as_ref().unwrap();
route.push(left.borrow().val);
Self::recur(&node.left, sum - left.borrow().val, res, route);
route.pop();
}
if node.right.is_some() {
let right = node.right.as_ref().unwrap();
route.push(right.borrow().val);
Self::recur(&node.right, sum - right.borrow().val, res, route);
route.pop();
}
}
}
```
<p align="center">
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52
problems/0404.左叶子之和.md
View File

@ -576,6 +576,58 @@ object Solution {
}
```
### Rust
**递归**
```rust
use std::cell::RefCell;
use std::rc::Rc;
impl Solution {
pub fn sum_of_left_leaves(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {
let mut res = 0;
if let Some(node) = root {
if let Some(left) = &node.borrow().left {
if left.borrow().right.is_none() && left.borrow().right.is_none() {
res += left.borrow().val;
}
}
res + Self::sum_of_left_leaves(node.borrow().left.clone())
+ Self::sum_of_left_leaves(node.borrow().right.clone())
} else {
0
}
}
}
```
**迭代：**
```rust
use std::cell::RefCell;
use std::rc::Rc;
impl Solution {
pub fn sum_of_left_leaves(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {
let mut res = 0;
let mut stack = vec![root];
while !stack.is_empty() {
if let Some(node) = stack.pop().unwrap() {
if let Some(left) = &node.borrow().left {
if left.borrow().left.is_none() && left.borrow().right.is_none() {
res += left.borrow().val;
}
stack.push(Some(left.to_owned()));
}
if let Some(right) = &node.borrow().right {
stack.push(Some(right.to_owned()));
}
}
}
res
}
}
```
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71
problems/0513.找树左下角的值.md
View File

@ -580,6 +580,77 @@ object Solution {
}
```
### rust
**层序遍历**
```rust
use std::cell::RefCell;
use std::collections::VecDeque;
use std::rc::Rc;
impl Solution {
pub fn find_bottom_left_value(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {
let mut queue = VecDeque::new();
let mut res = 0;
if root.is_some() {
queue.push_back(root);
}
while !queue.is_empty() {
for i in 0..queue.len() {
let node = queue.pop_front().unwrap().unwrap();
if i == 0 {
res = node.borrow().val;
}
if node.borrow().left.is_some() {
queue.push_back(node.borrow().left.clone());
}
if node.borrow().right.is_some() {
queue.push_back(node.borrow().right.clone());
}
}
}
res
}
}
```
**递归**
```rust
use std::cell::RefCell;
use std::rc::Rc;
impl Solution {
//*递归*/
pub fn find_bottom_left_value(root: Option<Rc<RefCell<TreeNode>>>) -> i32 {
let mut res = 0;
let mut max_depth = i32::MIN;
Self::traversal(root, 0, &mut max_depth, &mut res);
res
}
fn traversal(
root: Option<Rc<RefCell<TreeNode>>>,
depth: i32,
max_depth: &mut i32,
res: &mut i32,
) {
let node = root.unwrap();
if node.borrow().left.is_none() && node.borrow().right.is_none() {
if depth > *max_depth {
*max_depth = depth;
*res = node.borrow().val;
}
return;
}
if node.borrow().left.is_some() {
Self::traversal(node.borrow().left.clone(), depth + 1, max_depth, res);
}
if node.borrow().right.is_some() {
Self::traversal(node.borrow().right.clone(), depth + 1, max_depth, res);
}
}
}
```
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1
problems/0695.岛屿的最大面积.md
View File

@ -197,7 +197,6 @@ class Solution:
if not visited[i][j] and grid[i][j] == 1:
# 每一个新岛屿
self.count = 0
print(f'{self.count}')
self.bfs(grid, visited, i, j)
result = max(result, self.count)

11
problems/0707.设计链表.md
View File

@ -106,14 +106,11 @@ public:
// 在第index个节点之前插入一个新节点，例如index为0，那么新插入的节点为链表的新头节点。
// 如果index 等于链表的长度，则说明是新插入的节点为链表的尾结点
// 如果index大于链表的长度，则返回空
// 如果index小于0，则置为0，作为链表的新头节点。
// 如果index小于0，则在头部插入节点
void addAtIndex(int index, int val) {
if (index > _size) {
return;
}
if (index < 0) {
index = 0;
}
if(index > _size) return;
if(index < 0) index = 0;
LinkedNode* newNode = new LinkedNode(val);
LinkedNode* cur = _dummyHead;
while(index--) {

69
problems/二叉树中递归带着回溯.md
View File

@ -617,6 +617,75 @@ func _binaryTreePaths3(_ root: TreeNode, res: inout [String], paths: inout [Int]
}
```
### Rust
> 100.相同的树
```rsut
use std::cell::RefCell;
use std::rc::Rc;
impl Solution {
pub fn is_same_tree(
p: Option<Rc<RefCell<TreeNode>>>,
q: Option<Rc<RefCell<TreeNode>>>,
) -> bool {
match (p, q) {
(None, None) => true,
(None, Some(_)) => false,
(Some(_), None) => false,
(Some(n1), Some(n2)) => {
if n1.borrow().val == n2.borrow().val {
let right =
Self::is_same_tree(n1.borrow().left.clone(), n2.borrow().left.clone());
let left =
Self::is_same_tree(n1.borrow().right.clone(), n2.borrow().right.clone());
right && left
} else {
false
}
}
}
}
}
```
> 257.二叉树的不同路径
```rust
// 递归
use std::cell::RefCell;
use std::rc::Rc;
impl Solution {
pub fn binary_tree_paths(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<String> {
let mut res = vec![];
let mut path = vec![];
Self::recur(&root, &mut path, &mut res);
res
}
pub fn recur(
root: &Option<Rc<RefCell<TreeNode>>>,
path: &mut Vec<String>,
res: &mut Vec<String>,
) {
let node = root.as_ref().unwrap().borrow();
path.push(node.val.to_string());
if node.left.is_none() && node.right.is_none() {
res.push(path.join("->"));
return;
}
if node.left.is_some() {
Self::recur(&node.left, path, res);
path.pop(); //回溯
}
if node.right.is_some() {
Self::recur(&node.right, path, res);
path.pop(); //回溯
}
}
}
```
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