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Merge pull request #1412 from wzqwtt/tree13
添加(0700.二叉搜索树中的搜索、0098.验证二叉搜索树) Scala版本
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@ -589,7 +589,50 @@ function isValidBST(root: TreeNode | null): boolean {
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};
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```
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## Scala
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辅助数组解决:
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```scala
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object Solution {
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import scala.collection.mutable
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def isValidBST(root: TreeNode): Boolean = {
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var arr = new mutable.ArrayBuffer[Int]()
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// 递归中序遍历二叉树,将节点添加到arr
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def traversal(node: TreeNode): Unit = {
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if (node == null) return
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traversal(node.left)
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arr.append(node.value)
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traversal(node.right)
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}
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traversal(root)
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// 这个数组如果是升序就代表是二叉搜索树
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for (i <- 1 until arr.size) {
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if (arr(i) <= arr(i - 1)) return false
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}
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true
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}
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}
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```
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递归中解决:
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```scala
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object Solution {
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def isValidBST(root: TreeNode): Boolean = {
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var flag = true
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var preValue:Long = Long.MinValue // 这里要使用Long类型
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def traversal(node: TreeNode): Unit = {
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if (node == null || flag == false) return
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traversal(node.left)
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if (node.value > preValue) preValue = node.value
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else flag = false
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traversal(node.right)
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}
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traversal(root)
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flag
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}
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}
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```
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-----------------------
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<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>
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@ -363,7 +363,34 @@ function searchBST(root: TreeNode | null, val: number): TreeNode | null {
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};
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```
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## Scala
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递归:
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```scala
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object Solution {
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def searchBST(root: TreeNode, value: Int): TreeNode = {
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if (root == null || value == root.value) return root
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// 相当于三元表达式,在Scala中if...else有返回值
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if (value < root.value) searchBST(root.left, value) else searchBST(root.right, value)
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}
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}
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```
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迭代:
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```scala
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object Solution {
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def searchBST(root: TreeNode, value: Int): TreeNode = {
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// 因为root是不可变量,所以需要赋值给一个可变量
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var node = root
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while (node != null) {
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if (value < node.value) node = node.left
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else if (value > node.value) node = node.right
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else return node
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}
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null // 没有返回就返回空
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}
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}
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```
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-----------------------
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<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>
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