Merge pull request #1412 from wzqwtt/tree13

添加(0700.二叉搜索树中的搜索、0098.验证二叉搜索树) Scala版本
This commit is contained in:
程序员Carl
2022-07-01 09:45:26 +08:00
committed by GitHub
2 changed files with 70 additions and 0 deletions

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@ -589,7 +589,50 @@ function isValidBST(root: TreeNode | null): boolean {
};
```
## Scala
辅助数组解决:
```scala
object Solution {
import scala.collection.mutable
def isValidBST(root: TreeNode): Boolean = {
var arr = new mutable.ArrayBuffer[Int]()
// 递归中序遍历二叉树将节点添加到arr
def traversal(node: TreeNode): Unit = {
if (node == null) return
traversal(node.left)
arr.append(node.value)
traversal(node.right)
}
traversal(root)
// 这个数组如果是升序就代表是二叉搜索树
for (i <- 1 until arr.size) {
if (arr(i) <= arr(i - 1)) return false
}
true
}
}
```
递归中解决:
```scala
object Solution {
def isValidBST(root: TreeNode): Boolean = {
var flag = true
var preValue:Long = Long.MinValue // 这里要使用Long类型
def traversal(node: TreeNode): Unit = {
if (node == null || flag == false) return
traversal(node.left)
if (node.value > preValue) preValue = node.value
else flag = false
traversal(node.right)
}
traversal(root)
flag
}
}
```
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<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>

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@ -363,7 +363,34 @@ function searchBST(root: TreeNode | null, val: number): TreeNode | null {
};
```
## Scala
递归:
```scala
object Solution {
def searchBST(root: TreeNode, value: Int): TreeNode = {
if (root == null || value == root.value) return root
// 相当于三元表达式在Scala中if...else有返回值
if (value < root.value) searchBST(root.left, value) else searchBST(root.right, value)
}
}
```
迭代:
```scala
object Solution {
def searchBST(root: TreeNode, value: Int): TreeNode = {
// 因为root是不可变量所以需要赋值给一个可变量
var node = root
while (node != null) {
if (value < node.value) node = node.left
else if (value > node.value) node = node.right
else return node
}
null // 没有返回就返回空
}
}
```
-----------------------
<div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>