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Update 0343.整数拆分.md
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@ -262,10 +262,11 @@ class Solution:
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# 计算切割点j和剩余部分(i-j)的乘积,并与之前的结果进行比较取较大值
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dp[i] = max(dp[i], max((i - j) * j, dp[i - j] * j))
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dp[i] = max(dp[i], (i - j) * j, dp[i - j] * j)
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return dp[n] # 返回最终的计算结果
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```
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动态规划(版本二)
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```python
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