更新0094.城市间货物运输I.md Java版本解法

This commit is contained in:
Allen Guo
2024-08-07 07:13:31 -07:00
parent 8d3d4cec65
commit 00405e5192

View File

@ -392,6 +392,63 @@ Bellman_ford 是可以计算 负权值的单源最短路算法。
## 其他语言版本
### Java
```Java
public class Main {
// Define an inner class Edge
static class Edge {
int from;
int to;
int val;
public Edge(int from, int to, int val) {
this.from = from;
this.to = to;
this.val = val;
}
}
public static void main(String[] args) {
// Input processing
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int m = sc.nextInt();
List<Edge> edges = new ArrayList<>();
for (int i = 0; i < m; i++) {
int from = sc.nextInt();
int to = sc.nextInt();
int val = sc.nextInt();
edges.add(new Edge(from, to, val));
}
// Represents the minimum distance from the current node to the original node
int[] minDist = new int[n + 1];
// Initialize the minDist array
Arrays.fill(minDist, Integer.MAX_VALUE);
minDist[1] = 0;
// Starts the loop to relax all edges n - 1 times to update minDist array
for (int i = 1; i < n; i++) {
for (Edge edge : edges) {
// Updates the minDist array
if (minDist[edge.from] != Integer.MAX_VALUE && (minDist[edge.from] + edge.val) < minDist[edge.to]) {
minDist[edge.to] = minDist[edge.from] + edge.val;
}
}
}
// Outcome printing
if (minDist[n] == Integer.MAX_VALUE) {
System.out.println("unconnected");
} else {
System.out.println(minDist[n]);
}
}
}
```
### Python