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78 lines
1.8 KiB
Markdown
78 lines
1.8 KiB
Markdown
# [274. H-Index](https://leetcode.com/problems/h-index/)
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## 题目
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Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.
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According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."
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**Example 1**:
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```
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Input: citations = [3,0,6,1,5]
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Output: 3
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Explanation: [3,0,6,1,5] means the researcher has 5 papers in total and each of them had
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received 3, 0, 6, 1, 5 citations respectively.
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Since the researcher has 3 papers with at least 3 citations each and the remaining
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two with no more than 3 citations each, her h-index is 3.
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```
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**Note**:
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If there are several possible values for h, the maximum one is taken as the h-index.
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## 题目大意
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求 h-index。h-index 值的定义：如果他/她的 N 篇论文中至少有 h 引用，而其他 N-h 论文的引用数不超过 h 引用数。
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## 解题思路
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可以先将数组里面的数从小到大排序。因为要找最大的 h-index，所以从数组末尾开始往前找，找到第一个数组的值，小于，总长度减去下标的值，这个值就是 h-index。
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## 代码
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```go
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package leetcode
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// 解法一
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func hIndex(citations []int) int {
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n := len(citations)
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buckets := make([]int, n+1)
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for _, c := range citations {
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if c >= n {
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buckets[n]++
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} else {
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buckets[c]++
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}
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}
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count := 0
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for i := n; i >= 0; i-- {
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count += buckets[i]
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if count >= i {
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return i
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}
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}
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return 0
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}
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// 解法二
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func hIndex1(citations []int) int {
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quickSort164(citations, 0, len(citations)-1)
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hIndex := 0
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for i := len(citations) - 1; i >= 0; i-- {
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if citations[i] >= len(citations)-i {
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hIndex++
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} else {
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break
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}
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}
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return hIndex
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}
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``` |