mirror of
https://github.com/halfrost/LeetCode-Go.git
synced 2025-07-28 22:51:54 +08:00
90 lines
1.4 KiB
Markdown
90 lines
1.4 KiB
Markdown
# [110. Balanced Binary Tree](https://leetcode.com/problems/balanced-binary-tree/)
|
|
|
|
## 题目
|
|
|
|
|
|
Given a binary tree, determine if it is height-balanced.
|
|
|
|
For this problem, a height-balanced binary tree is defined as:
|
|
|
|
a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
|
|
|
|
**Example 1**:
|
|
|
|
Given the following tree [3,9,20,null,null,15,7]:
|
|
|
|
```
|
|
|
|
3
|
|
/ \
|
|
9 20
|
|
/ \
|
|
15 7
|
|
|
|
```
|
|
|
|
Return true.
|
|
|
|
**Example 2**:
|
|
|
|
Given the following tree [1,2,2,3,3,null,null,4,4]:
|
|
|
|
|
|
```
|
|
|
|
1
|
|
/ \
|
|
2 2
|
|
/ \
|
|
3 3
|
|
/ \
|
|
4 4
|
|
|
|
```
|
|
|
|
Return false.
|
|
|
|
|
|
## 题目大意
|
|
|
|
判断一棵树是不是平衡二叉树。平衡二叉树的定义是:树中每个节点都满足左右两个子树的高度差 <= 1 的这个条件。
|
|
|
|
|
|
## 解题思路
|
|
|
|
根据定义判断即可,计算树的高度是第 104 题。
|
|
|
|
|
|
|
|
|
|
## 代码
|
|
|
|
```go
|
|
|
|
package leetcode
|
|
|
|
/**
|
|
* Definition for a binary tree node.
|
|
* type TreeNode struct {
|
|
* Val int
|
|
* Left *TreeNode
|
|
* Right *TreeNode
|
|
* }
|
|
*/
|
|
func isBalanced(root *TreeNode) bool {
|
|
if root == nil {
|
|
return true
|
|
}
|
|
leftHight := depth(root.Left)
|
|
rightHight := depth(root.Right)
|
|
return abs(leftHight-rightHight) <= 1 && isBalanced(root.Left) && isBalanced(root.Right)
|
|
}
|
|
|
|
func depth(root *TreeNode) int {
|
|
if root == nil {
|
|
return 0
|
|
}
|
|
return max(depth(root.Left), depth(root.Right)) + 1
|
|
}
|
|
|
|
``` |