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66 lines
1.4 KiB
Markdown
66 lines
1.4 KiB
Markdown
# [1464. Maximum Product of Two Elements in an Array](https://leetcode.com/problems/maximum-product-of-two-elements-in-an-array/)
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## 题目
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Given the array of integers `nums`, you will choose two different indices `i` and `j` of that array. Return the maximum value of `(nums[i]-1)*(nums[j]-1)`.
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**Example 1**:
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```
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Input: nums = [3,4,5,2]
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Output: 12
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Explanation: If you choose the indices i=1 and j=2 (indexed from 0), you will get the maximum value, that is, (nums[1]-1)*(nums[2]-1) = (4-1)*(5-1) = 3*4 = 12.
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```
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**Example 2**:
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```
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Input: nums = [1,5,4,5]
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Output: 16
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Explanation: Choosing the indices i=1 and j=3 (indexed from 0), you will get the maximum value of (5-1)*(5-1) = 16.
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```
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**Example 3**:
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```
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Input: nums = [3,7]
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Output: 12
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```
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**Constraints**:
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- `2 <= nums.length <= 500`
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- `1 <= nums[i] <= 10^3`
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## 题目大意
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给你一个整数数组 nums，请你选择数组的两个不同下标 i 和 j，使 (nums[i]-1)*(nums[j]-1) 取得最大值。请你计算并返回该式的最大值。
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## 解题思路
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- 简单题。循环一次，按照题意动态维护 2 个最大值，从而也使得 `(nums[i]-1)*(nums[j]-1)` 能取到最大值。
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## 代码
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```go
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package leetcode
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func maxProduct(nums []int) int {
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max1, max2 := 0, 0
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for _, num := range nums {
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if num >= max1 {
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max2 = max1
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max1 = num
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} else if num <= max1 && num >= max2 {
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max2 = num
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}
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}
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return (max1 - 1) * (max2 - 1)
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}
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``` |