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96 lines
1.9 KiB
Markdown
96 lines
1.9 KiB
Markdown
# [1317. Convert Integer to the Sum of Two No-Zero Integers](https://leetcode.com/problems/convert-integer-to-the-sum-of-two-no-zero-integers/)
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## 题目
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Given an integer `n`. No-Zero integer is a positive integer which **doesn't contain any 0** in its decimal representation.
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Return *a list of two integers* `[A, B]` where:
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- `A` and `B` are No-Zero integers.
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- `A + B = n`
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It's guarateed that there is at least one valid solution. If there are many valid solutions you can return any of them.
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**Example 1**:
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```
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Input: n = 2
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Output: [1,1]
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Explanation: A = 1, B = 1. A + B = n and both A and B don't contain any 0 in their decimal representation.
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```
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**Example 2**:
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```
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Input: n = 11
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Output: [2,9]
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```
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**Example 3**:
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```
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Input: n = 10000
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Output: [1,9999]
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```
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**Example 4**:
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```
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Input: n = 69
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Output: [1,68]
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```
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**Example 5**:
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```
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Input: n = 1010
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Output: [11,999]
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```
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**Constraints**:
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- `2 <= n <= 10^4`
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## 题目大意
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「无零整数」是十进制表示中 不含任何 0 的正整数。给你一个整数 n，请你返回一个 由两个整数组成的列表 [A, B]，满足：
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- A 和 B 都是无零整数
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- A + B = n
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题目数据保证至少有一个有效的解决方案。如果存在多个有效解决方案，你可以返回其中任意一个。
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## 解题思路
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- 给定一个整数 n，要求把它分解为 2 个十进制位中不含 0 的正整数且这两个正整数之和为 n。
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- 简单题。在 [1, n/2] 区间内搜索，只要有一组满足条件的解就 break。题目保证了至少有一组解，并且多组解返回任意一组即可。
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## 代码
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```go
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package leetcode
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func getNoZeroIntegers(n int) []int {
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noZeroPair := []int{}
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for i := 1; i <= n/2; i++ {
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if isNoZero(i) && isNoZero(n-i) {
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noZeroPair = append(noZeroPair, []int{i, n - i}...)
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break
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}
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}
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return noZeroPair
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}
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func isNoZero(n int) bool {
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for n != 0 {
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if n%10 == 0 {
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return false
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}
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n /= 10
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}
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return true
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}
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``` |